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2 years ago

I need help w/ two questions. It includes the SAS and AAS postulates :) will award brainliest

Mathematics

1 answer:

WINSTONCH [101]2 years ago

4 0

5. You know angles LOY and ROY are congruent, and side OY is incident to both triangles LOY and ROY, which is of course congruent to itself. Triangles LOY and ROY will be congruent if sides OL and OR are also congruent.

6. Similar situation as in (5). MD is incident to both triangles MAD and DEM and is congruent to itself. Angles AMD and EDM are congruent. To use the AAS postulate, you need to know that angles MAD (or just A) and DEM (or just E) are congruent.

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si franco comió 8/3 de pizza y Fabián comió 5/6 de la misma pizza. ¿quien comió más ? si quedó 4/9 de pizza.

devlian [24]

Answer:

Franco comió 8/3 de pizza.

Fabián comió 5/6 de pizza.

Queremos saber quien comió más.

Entonces básicamente queremos ver cuál número es más grande, 8/3 o 5/6,

Podemos reescribir el primero como:

8/3 = (2 + 3 + 3)/3 = 2/3 + 3/3 + 3/3 = 2/3 + 1 + 1

= 2 + 2/3

En cambio, para el número 5/6, el numerador es menor que el denominador, entonces sabemos que:

5/6 < 1

Claramente podemos ver que 8/3 > 5/6

Entonces podemos concluir que Franco comió más.

8 0

3 years ago

A square field has an area of 121 square metre what is the length of each side

Tresset [83]

30.25 square meters because you would divide 121 by 4 because a square has 4 equal length sides.
Hope this helps

3 0

3 years ago

Determine 6th term in the geometric sequence whose first term is 3 and whose common ratio is -4.

GREYUIT [131]

$a_1=3$
$a_2=-4a_1$
$a_3=-4a_2=(-4)^2a_1$
$\cdots$
$a_6=-4a_5=\cdots=(-4)^5a_1$

$\implies a_6=(-4)^5\cdot3=-3072$

6 0

3 years ago

Find the work done by the force Bold Upper F equals xy Bold i plus (y minus x )Bold j over the straight line from (negative 1 co

aalyn [17]

Answer:

<h2>4/3 Joules </h2>

Step-by-step explanation:

Work is said to be done when force applied to an object causes the object to move through a distance.

Work done = Force * perpendicular distance.

$\int\limits^a_b {F} \, ds$

Given Force F = xy i + (y-x) j and a straight line (-1, -2) to (1, 2)

First we need to get the equation of the straight line given.

Given the slope intercept form y = mx+c

m is the slope

c is the intercept

m = y₂-y₁/x₂-x₁

m = 2-(-2)/1-(-1)

m = 4/2

m = 2

To get the slope we will substtutte any f the point and the slope into the formula y = mx+c

Using the point (1,2)

2 = 2+c

c = 0

y = 2x

Substituting y = 2x into the value of the force F = xy i + (y-x) j we will have;

F = x(2x) i + (2x - x) j

Using the coordinate (1, 2) as the value of s

$W = \int\limits^a_b ({2x^2 i + x j}) \, (i+2j)\\W = \int\limits^a_b ({2x^{2}+2x }) \, dx \\W = [\frac{2x^{3} }{3} +x^{2} ]\left \ x_2=1} \atop {x_1=-1}} \right.\\W = (2(1)^3/3 + 1^2) - (2(-1)^3/3 + (-1)^2)\\W =(2/3+1) - (-2/3+1)\\W = 2/3+2/3+1-1\\W = 4/3 Joules$

8 0

2 years ago

Find the area of each shape. Give awnser correct to one decimal place.

castortr0y [4]

Whats the numbers to solve

6 0

3 years ago