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givi [52]
2 years ago
10

A taxi company charges $2.25 for the first mile and then $0.20 per mile for each additional mile, or F = $2.25 + $0.20(m - 1) wh

ere F is the fare and m is the number of miles. If Juan's taxi fare was $6.05, how many miles did he travel in the taxi?
Mathematics
2 answers:
klio [65]2 years ago
7 0
F = 2.25 + 0.20(m-1)

F = 6.05

6.05 = 2.25 + 0.20(m-1)

Subtract 2.25 on both sides

6.05 - 2.25 = 0.20(m-1)

3.8 = 0.2(m-1)

Divide both sides by 0.2

3.8/0.2 = m - 1

19 = m - 1

Add 1 on both sides

19 + 1 = m

m = 20
 
If Juan's taxi fare was $6.05, then Juan traveled 20 miles in the taxi.
Lady bird [3.3K]2 years ago
6 0
In this problem, it is just a simple case of substitution and solving for the m which is the number of miles. Take the equation F = 2.25 + 0.20 (m-1). According to the given, the fare, or the F is 6.05 so with that, we can already solve the equation. this will be 6.05 = 2.25 + 0.20 (m-1). After that, all we have to do is just solve for the m. If we would solve for the m, we will end up with a final answer of 20. So all in all, the taxi was able to travel 20 miles on the 6.05 fare of Juan
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Answer:

$742

Step-by-step explanation:

To solve this, you need to figure out what 6% of 700 dollars is and then add that to 700. The easiest way to find the percentage of a number is to set it up in the equation:

6/100 = x/700  where 6 is the percentage of 700 (out of 100 because you can only get up to 100 percent in this case) and x is 6 percent of 700. when you cross multiply, you get 100x = 4200. Then you divide both sides by 100 to get x by itself. This will give you x = 42 Add this to 700 for 742 as the total amount that will be paid. Sorry if this first half was a little confusing

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2 years ago
A plane traveled from California and back. It took one hour longer on the way out than it did on the way back. The plane's avera
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Answer:

Option D is the correct answer.

Step-by-step explanation:

Let x be the one way distance and t be the time out.

Time taken for back = t-1

We have plane's average speed out was 300 mph and average speed on the way back was 350 mph.

That is

           \frac{x}{300}=t\texttt{ and }\frac{x}{350}=t-1

Dividing both equations

             \frac{\frac{x}{300}}{\frac{x}{350}}=\frac{t}{t-1}\\\\350t-350=300t\\\\t=7\texttt{ hours}

Time taken for back = t-1 = 7-1 = 6 hours.

Total time taken = 7 + 6 = 13 hours

Option D is the correct answer.

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Write an equation in slope-intercept form for each line.<br> (4,-1) and (-2,-1)
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With each line, a slope-intercept relationship (4,-1) and (-2,-1).

Y = 0 ,X = 5.

<h3>What is slope-intercept form?</h3>

The slope-intercept form is just a means of stating a line's equation so that both the slope (steepness) as well as y-intercept (where another line crosses this same vertical y-axis) are obvious. This expression is frequently referred to as y = mx + b.

<h3>According to the given information:</h3>

To begin, are using the slope formula to figure out the average slope between two points here.

Let:

x1 = 4

y1 = -1

x2 = -2

y2 = -1

m = (y2-y1)/(x2-x1)

= (-1 - (-1))/ (4-(-1))

= 0/5

= 0

So the slope is 0.

We must now calculate the y-intercept. This will be accomplished by converting a single of the points and also the slope together into a point-slope linear equation. y2-y1 = m(x2-x1).

Let’s plug in the point (5,0).

So we get y-(-0) = (0/5)(x-(-5)) ⇒  y+0

= (0/5)x +  0 ⇒  y

So,

Y = 0

X = 5

with each line, a slope-intercept relationship (4,-1) and (-2,-1).

Y = 0 ,X = 5

To know more about slope-intercept visit:

brainly.com/question/19824331

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