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kolezko [41]
2 years ago
15

Help me please please please

Mathematics
1 answer:
bogdanovich [222]2 years ago
5 0

Answer:

6th grade is more

Step-by-step explanation:

You might be interested in
The sum of two confescutive integers is at least 46. What is the least possibly pair of integers?
dezoksy [38]
An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.

1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46

So we have two possibilities: either #2 or #4. Find least possible pair of integers.

x= first integer
x+1= second integer

x + (x+1) >= 46
2x + 1 >=46
2x>=45
x>=22.5

Answer:
The first integer has to be greater than or equal to 22.5. Since integers are whole numbers, round up to the next whole number. The least possible integers are #2) 23 and 24.

Hope this helps! :)
3 0
3 years ago
PLEASE HELP!!
TEA [102]
1. The function of this graph is f(x) = 0.5x + -2 
Plug (-2) into the x variables so it looks like: 
f(-2) = 0.5 (-2) + -2
Then solve. 
Answer: f(-2) = -3 
**I'm not as sure about this one, so I might be wrong

2. 
For #8, the y-intercept is 4 (you're right) and it represents the initial distance before she started hiking (D) 
I tried to figure #9 out, but I couldn't find the answer. I came across a website that might help though: https://sciencing.com/determine-practical-domain-range-10052000.html
**I can't see #s 6 or 7
6 0
3 years ago
Sheldon earned $245.00 on Monday He is paid $35.00 per hour Whe
fredd [130]

Answer: 3:45PM

Step-by-step explanation: 245 / 35 = 7. 7 hours after 8:45AM is 3:45PM.

8 0
3 years ago
Read 2 more answers
A linear equation in the form of y=mx+b
enot [183]

Answer:

im sorry

Step-by-step explanation:

i need points or else ill fail

4 0
3 years ago
Explain why the X coordinates of the points where the graphs of the equations y=2^-x and y=4^x+3 intersects
sveta [45]
Hello,

y=2^(-x)
y=2^(2x)+3

==>2^(2x)+3=1/2^x
==>2^(3x)+3*2^x-1=0 (1)
Let's assume u=2^x
(1)==>u^3+3*u-1=0

which as 3 roots
u=0.322185354626 or
u = -0.161092677313 + i1.754380959784 or
u = -0.161092677313 - i1.754380959784.

Let's take the real solution

 0.322185354626=2^x
==>x=ln(0.322185354626) / ln(2)
 x=-1,6340371790199...

an other way is
f(x)=2^(3x)+3*2^x-1
f(-2)=1/64+3/4-1=-15/64 <0
f(-1)=1/8+1-1=1/8>0
==> there is a solution betheen -2<x<-1










6 0
3 years ago
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