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vovangra [49]
3 years ago
6

Please please help please help me help help me please help me

Mathematics
1 answer:
ryzh [129]3 years ago
5 0

Answer:

m=6/7

Step-by-step explanation:

(x,y)      (2,4)   (9,10)

10-4=6

9-2=7

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Read 2 more answers
Show with work please.
kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that \text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)

-\text{cos} \left(\theta\right)

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

\text{sec}(-\theta)=\text{sec}(\theta)

And, \text{sec}(\theta)=-0.73

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0
3 years ago
A star is a swirling mass of dense gases powered by thermonuclear reactions. The great solar furnace transforms 7 million tons o
marta [7]

Answer:

2.20752 x 10^{24}

Step-by-step explanation:

The first thing you have to do is to look for the number of seconds in one year. You have to multiply 365 days by 86,400 seconds.

  • 365 days refer to the total number of days per year
  • 86,400 seconds refer to the number of seconds per day

Let's solve.

  • 365 x 86,400 = 31,536,000 or 3.1536 x 10^{7}

<em>Therefore, one year has 3.1536 x </em>10^{7}<em> seconds.</em>

Next, you have to know the number of seconds in 10 billion years.

  • (3.1536 x 10^{7}) x  (1.0 x 10^{10}) = 3.1536 x 10^{17}

The last step is to multiply the number of seconds in 10 billion years to 7 million tons of mass per second.

  • (3.1536 x 10^{17}) x 7,000,000 = 2.20752 x 10^{24}
6 0
3 years ago
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