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Burka [1]
3 years ago
7

What is the measure of ∠4? Enter your answer in the box.

Mathematics
2 answers:
guajiro [1.7K]3 years ago
8 0

Answer:

∠ 4 = 59°

Step-by-step explanation:

q is a straight line, thus the 3 angles sum to 180° , that is

∠ 4 + 60° + 61° = 180°, that is

∠ 4 + 121° = 180° ( subtract 121° from both sides )

∠ 4 = 59°

charle [14.2K]3 years ago
4 0

Step-by-step explanation:

\angle 4, \:60\degree \:\&\:61\degree are straight line angles.

\therefore \angle \: 4 + 60 \degree + 60 \degree = 180\degree \\  \\  \therefore \:  \angle \: 4 = 180\degree - 121\degree \\  \\ \huge \red {\boxed {\therefore \:  \angle \: 4 = 59\degree}}

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Jobisdone [24]

Answer: 10

Step-by-step explanation:

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2 years ago
Adult humans have approximately 2.6 red blood cells and 3.92 white blood cells. About how many times greater is the number of re
kifflom [539]

Answer:

1.5 rounded to the nearest tenth

Step-by-step explanation:

To find how much greater WBC are from RBC we do,

3.92 ÷ 2.6

= 1.50769230769

Which is 1.5 rounded to the nearest tenth.

<em>Thus,</em>

<em>there are approximately 1.5 times WBC than RBC.</em>

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<em>Hope this helps :)</em>

4 0
3 years ago
Solution for dy/dx+xsin 2 y=x^3 cos^2y
vichka [17]
Rearrange the ODE as

\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y=x^3\cos^2y
\sec^2y\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y\sec^2y=x^3

Take u=\tan y, so that \dfrac{\mathrm du}{\mathrm dx}=\sec^2y\dfrac{\mathrm dy}{\mathrm dx}.

Supposing that |y|, we have \tan^{-1}u=y, from which it follows that

\sin2y=2\sin y\cos y=2\dfrac u{\sqrt{u^2+1}}\dfrac1{\sqrt{u^2+1}}=\dfrac{2u}{u^2+1}
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So we can write the ODE as

\dfrac{\mathrm du}{\mathrm dx}+2xu=x^3

which is linear in u. Multiplying both sides by e^{x^2}, we have

e^{x^2}\dfrac{\mathrm du}{\mathrm dx}+2xe^{x^2}u=x^3e^{x^2}
\dfrac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]=x^3e^{x^2}

Integrate both sides with respect to x:

\displaystyle\int\frac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]\,\mathrm dx=\int x^3e^{x^2}\,\mathrm dx
e^{x^2}u=\displaystyle\int x^3e^{x^2}\,\mathrm dx

Substitute t=x^2, so that \mathrm dt=2x\,\mathrm dx. Then

\displaystyle\int x^3e^{x^2}\,\mathrm dx=\frac12\int 2xx^2e^{x^2}\,\mathrm dx=\frac12\int te^t\,\mathrm dt

Integrate the right hand side by parts using

f=t\implies\mathrm df=\mathrm dt
\mathrm dg=e^t\,\mathrm dt\implies g=e^t
\displaystyle\frac12\int te^t\,\mathrm dt=\frac12\left(te^t-\int e^t\,\mathrm dt\right)

You should end up with

e^{x^2}u=\dfrac12e^{x^2}(x^2-1)+C
u=\dfrac{x^2-1}2+Ce^{-x^2}
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y=\tan^{-1}\left(\dfrac{x^2-1}2+Ce^{-x^2}\right)
5 0
3 years ago
Write an equation of the line that<br> passes through (-1,2) with a slope of 4
Iteru [2.4K]

Step-by-step explanation:

Hey there!

Given;

The points is; (-1 , 2) and slope is 4.

<em>Note:</em><em> </em><em>Use </em><em>one-point</em><em> formula</em><em>.</em>

<em>(y - y1) = m(x - x1)</em>

<em>~</em><em> </em><em>Put </em><em>all</em><em> values</em><em>.</em>

(y - 2) = 4(x + 1)

~ Simplify it.

(y - 2) = 4x + 4

4x - y + 6 = 0

Therefore, the required equation is; 4x-y+6=0.

<h3><em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em></h3>

6 0
2 years ago
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insens350 [35]

Answer:

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7 0
3 years ago
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