Initially, the velocity vector is $\langle 38cos(40^{\circ}),38sin(40^{\circ}) \rangle=\langle 29.110, 24.426 \rangle$ . At the same height, the x-value of the vector will be the same, and the y-value will be opposite (assuming no air resistance). Assuming perfect reflection off the ground, the velocity vector is the same. After 0.2 seconds at 9.8 seconds, the y-value has decreased by $4.9(0.2)^2$ , so the velocity is $\langle 29.110, 24.426-0.196 \rangle = \langle 29.110, 24.23 \rangle$ .

Converting back to direction and magnitude, we get $\langle r,\theta \rangle=\langle \sqrt{29.11^2+24.23^2},tan^{-1}(\frac{29.11}{24.23}) \rangle = \langle 37.87,50.2^{\circ}\rangle$

4 0

3 years ago

If youre reading this goodluck in school homie <3

bazaltina [42]

I needed this ! Thanks a lot

7 0

3 years ago

Read 2 more answers

Ditto sound waves espace room answers please I need this urgently

lord [1]

The actual question should be did the sound waves escape room?

Yes they can escape the room

Sound always needs a medium to travel through
If you close the room form all where that even air can't go outside you will be able to hear no sound coming from room .

6 0

2 years ago