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3 years ago

What is an earthquakeplease help

Physics

2 answers:

Digiron [165]3 years ago

6 0

earthquake is the shaking of the earths surface causing rapid movement of the earths rocky outer layer .

siniylev [52]3 years ago

4 0

Answer:

when the earth quakes...

Explanation:

or An earthquake is caused by a sudden slip on a fault, When the stress on the edge overcomes the friction, there is an earthquake that releases energy in waves that travel through the earth's crust and cause the shaking that we feel.

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Which type of pollution occurs when small particles of soil are suspended in water?

vova2212 [387]

The type of pollution when small particles of soil are suspended in the water is called Suspended Matter Pollution. This type of pollution happens when soil enter the water and do not mix in with the water molecules.

7 0

3 years ago

Read 2 more answers

A solid conducting sphere has net positive charge and radiusR = 0.600 m . At a point 1.20 m from the center of the sphere, the e

gayaneshka [121]

Answer:

V_inside = 36 V

Explanation:

Given

We are given a sphere with a positive charge q with radius R = 0.400 m Also, the potential due to this charge at distance r = 1.20 m is V = 24.0 V.

Required

We are asked to calculate the potential at the centre of the sphere

Solution

The potential energy due to the sphere is given by equation

V = (1/4*π*∈o) × (q/r) (1)

Where r is the distance where the potential is measured, it may be inside the sphere or outside the sphere. As shown by equation (1) the potential inversely proportional to the distance V

V ∝ 1/r

The potential at the centre of the sphere depends on the radius R where the potential is the same for the entire sphere. As the charge q is the same and the term (1/4*π*∈o) is constant we could express a relation between the states , e inside the sphere and outside the sphere as next

V_1/V_2=r_2/r_1

V_inside/V_outside = r/R

V_inside = (r/R)*V_outside (2)

Now we can plug our values for r, R and V_outside into equation (2) to get V_inside

V_inside = (1.2 m )/(0.600)*18

= 36 V

V_inside = 36 V

7 0

3 years ago

Read 2 more answers

A car moving at some speed hits the brakes and skids to a stop after 13 m on a level road. If the coefficient of friction for th

vesna_86 [32]

Answer:

12.974 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s²

$\mu$ = Coefficient of friction =0.66

a = Acceleration = $\mu g$

$v^2-u^2=2as\\\Rightarrow -u^2=2\mu gs-v^2\\\Rightarrow u=\sqrt{v^2-2\mu gs}\\\Rightarrow u=\sqrt{0^2-2\times -(9.81\times 0.66)\times 13}\\\Rightarrow u=12.974\ m/s$

Car's original speed before braking was 12.974 m/s

6 0

4 years ago

Devise an exponential decay function that fits the given data, then answer the accompanying questions. Be sure to identify the

7nadin3 [17]

Answer:

22145.27733 ft

124984.76055 ft

Explanation:

The equation of pressure is

$P=P_0e^{-kh}$

where,

$P_0$ =Atmospheric pressure = 800 mbar

k = Constant

h = Altitude = 35000 ft

$P=\dfrac{1}{3}P_0$

$\dfrac{1}{3}P_0=P_0e^{-k35000}\\\Rightarrow \dfrac{1}{3}=e^{-k35000}\\\Rightarrow 3=e^{k35000}\\\Rightarrow ln3=k35000\\\Rightarrow k=\dfrac{ln3}{35000}\\\Rightarrow k=3.13\times 10^{-5}$

Now

$P=\dfrac{1}{2}P_0$

$ln2=kh\\\Rightarrow h=\dfrac{ln2}{k}\\\Rightarrow h=\dfrac{ln2}{3.13\times 10^{-5}}\\\Rightarrow h=22145.27733\ ft$

The altitude will be 22145.27733 ft

$P=0.02P_0$

$0.02P_0=P_0e^{-kh}\\\Rightarrow 0.02=e^{-3.13\times 10^{-5}h}\\\Rightarrow ln0.02=-3.13\times 10^{-5}h\\\Rightarrow h=\dfrac{ln0.02}{-3.13\times 10^{-5}}\\\Rightarrow h=124984.76055\ ft$

The elevation is 124984.76055 ft

6 0

3 years ago

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Snezhnost [94]

Frozen water has move volume than water in liquid form

8 0

3 years ago

What is an earthquakeplease help ​

What is an earthquakeplease help