Ask question

Ask question

All categories

3 years ago

6

Objects 1 and 2 attract each other with a gravitational force of 16 units. If the mass of object 1 is one-third the original val

ue AND the mass of object 2 is doubled AND the distance separating objects 1 and 2 is doubled, then the new gravitational force will be _____ units.

1 answer:

serious [3.7K]3 years ago

6 0

Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant, which has the same value throughout our universe.

D is the distance between both objects.

so, now some numbers change

Fgravitynew = G*((1/3)*mass1*2*mass2)/(2D)² =

= G*((2/3)*mass1*mass2)/(4D²) =

= (2/3)* (G*(mass1*mass2)/D²) / 4 =

= ((2/3)/4) * G*(mass1*mass2)/D² =

= (2/12) * Fgravity = Fgravity/6

the new gravitational force will be 16/6 = 8/3 units.

You might be interested in

A car is moving in uniform circular motion. If the cars speed were to double to keep the car moving with the same radius the acc

Stells [14]

Answer:

<em>The centripetal acceleration would increase by a factor of 4</em>

<em>Correct choice: B.</em>

Explanation:

<u>Circular Motion</u>

The circular motion is described when an object rotates about a fixed point called center. The distance from the object to the center is the radius. There are other magnitudes in the circular motion like the angular speed, tangent speed, and centripetal acceleration. The formulas are:

$v_t=w\ r$

$\displaystyle a_c=\frac{v_t^2}{r}$

If the speed is doubled and the radius is the same, then

$\displaystyle a_c=\frac{(2v_t)^2}{r}$

$\displaystyle a_c=4\frac{v_t^2}{r}$

The centripetal acceleration would increase by a factor of 4

Correct choice: B.

5 0

3 years ago

A horse has an acceleration of 2 m/s2. If it starts from rest, how fast is it going after 1.7 seconds?

fgiga [73]

(2 m/s²) · (1.7 s) = 3.4 m/s

6 0

3 years ago

Read 2 more answers

The element that has an average amu of 40 is represented by the symbol Zr on the Periodic Table of Elements. True False Question

Gnom [1K]

Answer:

False

Explanation:

Becuase the average amu of 40 is represented

6 0

3 years ago

Computers A and B implement the same ISA. Computer A has a clock cycle time of 200 ps and an effective CPI of 1.5 for some progr

lesya692 [45]

Answer:

Computer A is 1.41 times faster than the Computer B

Explanation:

Assume that number of instruction in the program is 1

Clock time of computer A is $CT_{A} =200 ps$

Clock time of computer B is $CT_{B} =250 ps$

Effective CPI of computer A is $CPI_{A} =1.5$

Effective CPI of computer B is $CPI_{B} =1.7$

CPU time of A is

$CPU_{time}=instructions \times CPA_{A} \times CT_{A}\\CPU_{time}=1 \times 1.5 \times 200=300 sec$

CPU time of B is

$CPU_{time}=instructions \times CPA_{B} \times CT_{B}\\CPU_{time}=1 \times 1.7 \times 250=425 sec$

Hence Computer A is Faster by $\frac{425}{300} =1.41$

Computer A is 1.41 times faster than the Computer B

4 0

3 years ago

1. If a model train car with a momentum of 12 kg•m/s collides with a 2 kg model train car that is not moving, what is the total

wariber [46]

Answer:

$P_{f} = 12 \ kg.m/s$

Explanation:

Given data:

Momentum of moving model train, $P_{1} = 12 \ kg.m/s$

Mass of the stationary model train, $m = 2 \ kg$

Initial speed of the stationary model train, $v = 0$

Assume there is no external force is acting on the given train system.

In this case, the total linear momentum of the trains would be conserved.

Let the final linear momentum of the trains be $P_{f}.$

Thus,

$P_{i} = P_{f}$

$P_{1} + P_{2} = P_{f}$

$P_{1} + mv = P_{f}$

$12 + 2 \times 0 = P_{f}$

$\Rightarrow \ P_{f} = 12 \ kg.m/s.$

7 0

3 years ago