I had this same question yesterday it was c 2x+3x+9x
The answer is easy
So we need to fund m2NLM
The answer is c
yuhhh get into ittttttt luv
Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:
1. ABC against DEF
2. ABD against CEF
3. ABE against CDF
4. ABF against CDE
5. ACD against BFE
6. ACE against BDF
7. ACF against BDE
8. ADE against BCF
9. ADF against BCE
10. AEF against BCD
I believe there are 12 combinations... I just can't think of the last 2 though.
We breakdown the components of the distances.
(1) 90 miles west.
x - component = -90 miles
y - component = 0 miles
(2) 80 miles, northwest (120°)
x - component = (80 miles)*(sin 30°) = 40 miles (negative)
y - component =(80 miles)*(cos 30°) = 69.282 miles (positive)
Solve for the distance,
√(-90 - - 40)² + (69.282 miles)² = <em>147.31 miles</em>