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Viefleur [7K]
3 years ago
10

If PR=40, what are PQ and QR?

Mathematics
2 answers:
RUDIKE [14]3 years ago
8 0

Answer:

B

Step-by-step explanation:

I did it in my head but pretty much just add the 5x-2 and x+ 12 then set it equal to 40. u get x = 5. plug x back in and you get 23 and 17

Sunny_sXe [5.5K]3 years ago
4 0

Answer:

The answer is B

Step-by-step explanation:

5x - 2 + x + 12 = 40

6x + 10 = 40

6x = 30

x = 5

5(5) - 2

25 - 2

PQ = 23

(5) + 12

QR = 17

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Mashcka [7]

Answer:

D. the number of hours the veterinarian works a week

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3 years ago
Solve the equation uding the most direct method: 3x(x+6)=-10?​
Tanzania [10]

To solve this problem, you will use the distributive property to create an equation that can be rearranged and solved using the quadratic formula.

<h3>Distribute</h3>

Use the distributive property to distribute 3x into the term (x + 6):

3x(x+6)=-10

3x^2+18x=-10

<h3>Rearrange</h3>

To create a quadratic equation, add 10 to both sides of the equation:

3x^2+18x+10=-10+10

3x^2+18x+10=0

<h3>Use the Quadratic Formula</h3>

The quadratic formula is defined as:

\displaystyle x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The model of a quadratic equation is defined as ax² + bx + c = 0. This can be related to our equation.

Therefore:

  • a = 3
  • b = 18
  • c = 10

Set up the quadratic formula:

\displaystyle x=\frac{-18 \pm \sqrt{(18)^2 - 4(3)(10)}}{2(3)}

Simplify by using BPEMDAS, which is an acronym for the order of operations:

Brackets

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

Use BPEMDAS:

\displaystyle x=\frac{-18 \pm \sqrt{324 - 120}}{6}

Simplify the radicand:

\displaystyle x=\frac{-18 \pm \sqrt{204}}{6}

Create a factor tree for 204:

204 - 1, 2, 3, 4, 6, 12, 17, 34, 51, 68, 102 and 204.

The largest factor group that creates a perfect square is 4 × 51. Therefore, turn 204 into 4 × 51:

\sqrt{4\times51}

Then, using the Product Property of Square Roots, break this into two radicands:

\sqrt{4} \times \sqrt{51}

Since 4 is a perfect square, it can be evaluated:

2 \times \sqrt{51}

To simplify further for easier reading, remove the multiplication symbol:

2\sqrt{51}

Then, substitute for the quadratic formula:

\displaystyle x=\frac{-18 \pm 2\sqrt{51}}{6}

This gives us a combined root, which we should separate to make things easier on ourselves.

<h3>Separate the Roots</h3>

Separate the roots at the plus-minus symbol:

\displaystyle x=\frac{-18 + 2\sqrt{51}}{6}

\displaystyle x=\frac{-18 - 2\sqrt{51}}{6}

Then, simplify the numerator of the roots by factoring 2 out:

\displaystyle x=\frac{2(-9 + \sqrt{51})}{6}

\displaystyle x=\frac{2(-9 - \sqrt{51})}{6}

Then, simplify the fraction by reducing 2/6 to 1/3:

\boxed{\displaystyle x=\frac{-9 + \sqrt{51}}{3}}

\boxed{\displaystyle x=\frac{-9 - \sqrt{51}}{3}}

The final answer to this problem is:

\displaystyle x=\frac{-9 + \sqrt{51}}{3}

\displaystyle x=\frac{-9 - \sqrt{51}}{3}

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2 years ago
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Answer:

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Step-by-step explanation:

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\frac{12}{55} Answer

Hope this helps!

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Just need help with this !
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Answer:

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