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Zinaida [17]
3 years ago
8

Construct the graph of the direct proportion y=kx for

Mathematics
1 answer:
goldenfox [79]3 years ago
6 0

Welp,  I think this is it?

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Ayudaaaaaaaaaaaaaaaaaaaaaaa
Kitty [74]

Answer:

10

Step-by-step explanation:

8 0
3 years ago
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NO LINKS!!! Part 1: y = x^3<br><br>Shape:<br>Domain:<br>Range: <br>Locater point:​
LiRa [457]

Answer:

Shape: <em>Not sure what to put</em>

Domain: ( -oo, oo )

Range: ( -oo, oo )

Locater point: ( 0, 0 )

Step-by-step explanation:

Shape - You have the shape on the graph

Domain and Range - Both go on forever since there is no hole/interruption

Locater Point: I would say origin because it is the closest thing to a vertex, which is an example of a locater point.

Hopefully this helps!

Brainliest please?

5 0
3 years ago
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Add 17/99 + 27/99 + 15/99
Helen [10]

Answer:

59/99

Step-by-step explanation:

Since the denominator is the same you add the numerator values for each fraction  27+17+15 = 59

8 0
3 years ago
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Simplify the expression (√3 + i)(√3- i) and write the result in the form a+bi.
goblinko [34]

Answer: D) 4

Step-by-step explanation:

8 0
3 years ago
StartFraction (negative 7) squared Over (negative 7) Superscript negative 1 EndFraction
Elan Coil [88]

Answer:

-343

Step-by-step explanation:

Given the expression:   \dfrac{(-7)^2}{(-7)^{-1}}

You will notice that the terms in the numerator and denominator have the same base (-7).

This makes it very easy to simplify by applying the division law of indices.

\dfrac{a^x}{a^y} =a^{x-y}

Therefore:

\dfrac{(-7)^2}{(-7)^{-1}}=(-7)^{2-(-1)}\\=(-7)^{2+1}\\=(-7)^3\\=-7 X -7 X -7\\=-343

8 0
4 years ago
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