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3 years ago

Select the correct answer.

Mathematics

2 answers:

Kruka [31]3 years ago

8 0

Answer:

C. x + 5 = (x + 5) − 5, which has no solution

Step-by-step explanation:

Jenna's age Jessica's age

today x x + 5

in 5 years x+5

5 years ago x + 5 - 5

Equality x + 5 = x + 5 - 5

=> x + 5 = x

The equation is x + 5 = ( x + 5 ) -5

jek_recluse [69]3 years ago

6 0

Answer: its either A or E but im 90% sure its E

Step-by-step explanation:

if its wrong im sorry

You might be interested in

MAKE T THE SUBJECT OF FORMULA G=T+3/7

kaheart [24]

Step-by-step explanation:

G= T+3/7

G-3/7=T

T= G-3/7

6 0

2 years ago

Is 4.71 bigger than 7.39

Alex Ar [27]

Answer:

no it is not bigger think of it of money what would you rather have 4 dollars and 71 cents or 7 dollars and 39 cents well obviously you would the the 7 dollars

8 0

3 years ago

At time t hours after taking the cough suppressant hydrocodone bitartrate, the amount, A, in mg, remaining in the body is given

Nostrana [21]

Answer:

a. The initial amount was 10 mg.

b. The percentage of the drug leaving the body each hour is 0.18, this is 18% per hour.

c. The amount of drug that remains in the body 6 hours after dosing is 3.04 mg.

d. The time until only 1 mg of the drug remains in the body is 11.6 hours.

Step-by-step explanation:

You know that at time t hours after taking the cough suppressant hydrocodone bitartrate, the amount, A, in mg, remaining in the body is given by :

$A=10*(0.82)^{t}$

a. The initial quantity occurs when time t is the initial t, that is, t is equal to 0. Then:

$A=10*(0.82)^{t}=10*(0.82)^{0}=10*1\\$

A=10

The initial amount was 10 mg.

b. Considering that an exponential growth is determined by:

$A=A0*(1-r)^{t}$ , where A is the amount after a certain number of a certain time, Ao is the initial amount, r is the rate and t is the time, so the percentage of the drug that leaves the body each hour is :

1-r=0.82

Solving:

1-r -1= 0.82 -1

-r= -0.18

r= 0.18

The percentage of the drug leaving the body each hour is 0.18, this is 18% per hour.

c. The amount of drug that remains in the body 6 hours after dosing is when t = 6:

$A=10*(0.82)^{6}$

Solving:

A= 3.04 mg

The amount of drug that remains in the body 6 hours after dosing is 3.04 mg.

d. The time that passes until only 1 mg of the drug remains in the body is calculated taking into account that A = 1 mg:

$1=10*(0.82)^{t}$

Solving:

$0.1=(0.82)^{t}$

㏒ 0.1= t*㏒ 0.82

㏒ 0.1 ÷ ㏒ 0.82= t

11.6 hours= t

The time until only 1 mg of the drug remains in the body is 11.6 hours.

4 0

3 years ago

Which of the following shows the extraneous solution(s) to the logarithmic equation? log4 (x) + log4(x - 3) = log4 (-7x + 21)

Salsk061 [2.6K]

First join the log4 on the left:

log4( x*(x-3) = log4(-7x+21)

Then x = -7, works: -7*(-10)=70 = -7*(-7)+21

x=-3, 18 = 42, does not work

x=3 0=0 works,

However, when one puts x = -7 in the *original* exression, log4(-7) or log4(-10) do not exist (you know why?). So x= -7 is extraneous.

Now x=3 gives log4(0) on the left and right, which does not exist.

So, C is the answer, both are extraneous. Seem to work but indeed don't work in the *original* equation

6 0

3 years ago

Read 2 more answers

A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as ed

zhuklara [117]

Answer:

For the cost from the two methods to be equal, 3,200 books have to be produced

Step-by-step explanation:

In this question, we are asked to calculate the number of books that will be produced for two methods of production having different fixed and variable costs to have the same production cost.

Since the number of books is something we do not know, let’s represent it with a variable called c.

For the first production method, the cost of production will be ; 58,881 + 8.50c

For the second production method, the cost of production will be; 18,081 + 21.25c

Now since they are said to be equal, we proceed to equate both;

58,881 + 8.5c = 18,081 + 21.25c

58,881-18,081 = 21.25c - 8.5c

40,800 = 12.75c

c = 40,800/12.75

c = 3,200 books

4 0

3 years ago