1. x + 18 = 57
2. Subtract 18 from both sides
x = 39
This is a great question!
To determine the probability with which two sweets are not the same, you would have to subtract the probability with which two sweets are the same from 1. That would only be possible if she chose 2 liquorice sweets, 5 mint sweets and 3 humburgs -
As you can see, the first time you were to choose a Liquorice, there would be 12 out of the 20 sweets present. After taking that out however, there would be respectively 11 Liquorice out of 19 remaining. Apply the same concept to each of the other sweets -
____
Calculate the probability of drawing 2 of each, add them together and subtract from one to determine the probability that two sweets will not be the same type of sweet!
<u><em>Thus, the probability should be 111 / 190</em></u>
Answer:
S=-3
Step-by-step explanation:
Set p(x) = 0 and solve for x.
x^3 - 4x^2 + 3x - 12 = 0
x^3 - 4x^2 ... + 3x - 12 = 0, cut in half and factor
x^2 (x-4) ... +3 (x-4) = 0, regroup
(x^2 + 3) (x-4) = 0, set each part equal to zero and solve
x^2 + 3 = 0, subtract 3 from both sides
x^2 = -3, take square root of both sides
x = sqrt (-3) which is imaginary.
x-4 = 0, add 4 to both sides
x = 4
Since we do not want complex/imaginary numbers involved, our answer is 4. They will break even in 4 years.
He would need to mow 5 lawns. To solve this, just divide 209 by 47. It will be 4.4, but since he has to mow full lawns it would be 5.