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The Slow Ball Challenge or The Fast Ball Challenge.

cupoosta [38]

Answer:

Fast ball challenge

Step-by-step explanation:

Given

Slow Ball Challenge

$Pitches = 7$

$P(Hit) = 80\%$

$Win = \$60$

$Lost = \$10$

Fast Ball Challenge

$Pitches = 3$

$P(Hit) = 70\%$

$Win = \$60$

$Lost = \$10$

Required

Which should he choose?

To do this, we simply calculate the expected earnings of both.

Considering the slow ball challenge

First, we calculate the binomial probability that he hits all 7 pitches

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

Where

$n = 7$ --- pitches

$x = 7$ --- all hits

$p = 80\% = 0.80$ --- probability of hit

So, we have:

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

$P(7) =^7C_7 * 0.80^7 * (1 - 0.80)^{7 - 7}$

$P(7) =1 * 0.80^7 * (1 - 0.80)^0$

$P(7) =1 * 0.80^7 * 0.20^0$

Using a calculator:

$P(7) =0.2097152$ --- This is the probability that he wins

i.e.

$P(Win) =0.2097152$

The probability that he lose is:

$P(Lose) = 1 - P(Win)$ ---- Complement rule

$P(Lose) = 1 -0.2097152$

$P(Lose) = 0.7902848$

The expected value is then calculated as:

$Expected = P(Win) * Win + P(Lose) * Lose$

$Expected = 0.2097152 * \$60 + 0.7902848 * \$10$

Using a calculator, we have:

$Expected = \$20.48576$

Considering the fast ball challenge

First, we calculate the binomial probability that he hits all 3 pitches

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

Where

$n = 3$ --- pitches

$x = 3$ --- all hits

$p = 70\% = 0.70$ --- probability of hit

So, we have:

$P(3) =^3C_3 * 0.70^3 * (1 - 0.70)^{3 - 3}$

$P(3) =1 * 0.70^3 * (1 - 0.70)^0$

$P(3) =1 * 0.70^3 * 0.30^0$

Using a calculator:

$P(3) =0.343$ --- This is the probability that he wins

i.e.

$P(Win) =0.343$

The probability that he lose is:

$P(Lose) = 1 - P(Win)$ ---- Complement rule

$P(Lose) = 1 - 0.343$

$P(Lose) = 0.657$

The expected value is then calculated as:

$Expected = P(Win) * Win + P(Lose) * Lose$

$Expected = 0.343 * \$60 + 0.657 * \$10$

Using a calculator, we have:

$Expected = \$27.15$

So, we have:

$Expected = \$20.48576$ -- Slow ball

$Expected = \$27.15$ --- Fast ball

The expected earnings of the fast ball challenge is greater than that of the slow ball. Hence, he should choose the fast ball challenge.

5 0

3 years ago

camelbeck mountain has an elevation change of 1,264 feet. how many pennies would it take to make a stack that high? show all wor

mixer [17]

Camel back Mountain = 15,168 inches (1,264 feet)
1 Penny = 0.061 (.0610) Inches
10 Penny = 0.61 (.610) Inches
100 Penny = 6.1 (6.10) Inches
1,000 Penny = 61 (61.0) Inches
10,000 Penny = 610 (610.0) Inches
-SOLVING-
10,000 Penny = 610 inches PLUS
1,000 Penny = 61 inches AND 61 inches x 5 = 305 (5,000 Penny)
100 Penny = 6.1 inches PLUS
10 Penny = 0.61 inches AND 0.61 inches x 6 = 3.66 (60 Penny)
1 Penny = 0.061 inches AND 0.061 inches x 8 = 0.488 (8 Penny)
-FINAL ANSWER-
610 + 305 + 6.1 + 3.66 + 0.488 = 925.248 Penny it would take.

8 0

2 years ago

Solve using substitution 7x-6y=-20 Y=1

maksim [4K]

Answer:

x = -2

Step-by-step explanation:

7x -6y = -20

y=1

7x - 6 = -20

7x = -14

x = -2

4 0

2 years ago

A study of 218 students at a major state university suggests a link between time spent on social networking websites and grade p

zheka24 [161]

Answer:

a) The study suggests a negative correlation because the study shows that as time spent on social networking websites Increases, grade point average tends to decrease.

b) While it is possible that there is a cause and effect relationship, it is not necessarily the case.

Step-by-step explanation:

Since the study submitted that, students who rarely never used social networking websites had higher grade point averages than students who use social networking websites. It implies a negative relationship. Thus, the option given above is the correct answer.

Similarly, the study might imply some cause and effect relationship but it is not necessarily to be the case. That is, low grade point could result into more time with social networking website. This is not necessary to be TRUE!

4 0

3 years ago

Someone please help me with this!

tigry1 [53]

Answer:

remove the bracket on the other side by multiplying 180 by (2-n)

subtract 360 from 1260 to remain with -180n on the other side

divide both sides by -180n

then n become -5

5 0

3 years ago