Answer: 15.85km
Step-by-step explanation:
The car starts at the point (0,0)
Let's define east as the positive x-axis and north as the positive y-axis.
first, the car travels 10km southeast, so the angle is -45° from the east.
Then the new position of the car is:
(10km*cos(-45°), 10km*sin(-45°)) = (7.07km, -7.07km)
Now, from this point the car travels 15km with an angle of 60° (counting from the east)
So the new position is:
(7.07km + 15km*cos(60°), -7.07km + 15km*sin(60°)) = (14.57km , 5.91km)
The magnitude of a vector (x, y) is √(x^2 + y^2)
So the magnitude of the vector (14.57km , 5.91km) is:
√((14.57km)^2 + (5.91km)^2) = 15.85km
