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Masteriza [31]
3 years ago
5

Use slope to determine if lines PQ and RS are parallel, perpendicular, or neither. P(-4,17),Q (1,-3), R(-9,3),S(-5,4)

Mathematics
1 answer:
vitfil [10]3 years ago
3 0

Answer:

Both lines are perpendicular

Step-by-step explanation:

We want to determine the relationship between the two lines.

The best thing to do is to calculate the slope of the two lines;

Mathematically;

Slope = y2-y1/x2-x1

For PQ; slope will be;

(-3-17)/(1-(-4) =-20/5 = -4

For RS

slope = (4-3)/(-5-(-9)) = 1/4

Now we have -4 and 1/4 as slopes

The product of both is 1/4 * -4 = -1

When two lines are perpendicular, the product of their slopes is -1

We can conclude that both lines are perpendicular to one another

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The vertices of a square ABCD are labelled anti-clockwise. A and C are the vertices of an equilateral triangle AEC, whose vertic
belka [17]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
PLEASE HURRY!!! what is the slope of the graph?
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8 0
3 years ago
Read 2 more answers
A candy store makes a 13–pound mixture of gummy bears, jelly beans, and gobstoppers. The cost of gummy bears is $1.00 per pound,
bulgar [2K]
X = gummy bears, y = jelly beans, z = gobstoppers
x + y + z = 13
x + 2y + 2z = 20
x = 3y

3y + y + z = 13
4y + z = 13

3y + 2y + 2z = 20
5y + 2z = 20

4y + z = 13....multiply by -2
5y + 2z = 20
-----------------
-8y - 2z = -26
5y + 2z = 20
---------------add
-3y = -6
y = 2........2 lbs jelly beans

x = 3y
x = 3(2)
x = 6....6 lbs gummy bears

x + y + z = 13
6 + 2 + z = 13
8 + z = 13
z = 13 - 8
z = 5........5 lbs gobstoppers

so we have : 6 lbs gummy bears (x), 2 lbs jelly beans (y), and 5 lbs gobstoppers (z)




5 0
3 years ago
Read 2 more answers
1. Simplify the expression: <img src="https://tex.z-dn.net/?f=%282x%5E%7B2%7D%20y%29x%5E%7B3%7D" id="TexFormula1" title="(2x^{2}
liubo4ka [24]

Answer:

2·x^5·y

Step-by-step explanation:

2x^5y

4 0
3 years ago
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