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Masteriza [31]
3 years ago
5

Use slope to determine if lines PQ and RS are parallel, perpendicular, or neither. P(-4,17),Q (1,-3), R(-9,3),S(-5,4)

Mathematics
1 answer:
vitfil [10]3 years ago
3 0

Answer:

Both lines are perpendicular

Step-by-step explanation:

We want to determine the relationship between the two lines.

The best thing to do is to calculate the slope of the two lines;

Mathematically;

Slope = y2-y1/x2-x1

For PQ; slope will be;

(-3-17)/(1-(-4) =-20/5 = -4

For RS

slope = (4-3)/(-5-(-9)) = 1/4

Now we have -4 and 1/4 as slopes

The product of both is 1/4 * -4 = -1

When two lines are perpendicular, the product of their slopes is -1

We can conclude that both lines are perpendicular to one another

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Which equation is equivalent to log Subscript 3 Baseline (x + 5) = 2?
adell [148]

Answer:

The correct option is right-bracket squared 3 squared =x+5

Step-by-step explanation:

The equation is \log _{3}(x+5)=2

Option a: \log _{3}(x+5)=3^{2}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option a is not equivalent to \log _{3}(x+5)=2

Option b: \log _{3}(x+5)=2^{3}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option b is not equivalent to \log _{3}(x+5)=2

Option c: x+5=3^{2}

This is possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option c is equivalent to \log _{3}(x+5)=2

Option b: x+5=2^{3}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option b is not equivalent to \log _{3}(x+5)=2

Thus, the correct option is c: x+5=3^{2}

Hence, the equation x+5=3^{2} is equivalent to \log _{3}(x+5)=2

8 0
4 years ago
What is an equation of the line that passes through the points (3,-3) and (-3,-3)?
victus00 [196]
First find the gradient of the line
Change in y/change in x
-3–3/-3-3
0/-6
=0 ( so the gradient m is equal to zero)

Y=0x+c

Input the coordinates of one point to find c

-3=(0*3)+c
-3=c


So the equation is
Y= -3


3 0
3 years ago
A<br> 19 = 548 and a<br> 33 = 968<br> Find a<br> 27
s2008m [1.1K]

Answer:

The value of a₂₇ is 788

Step-by-step explanation:

a₁₉ = 548

a₃₃ = 968

Now,

a₁₉ = 548 can be written as

a + 18d = 548 ...(1) and

a₃₃ = 968 can be written as

a + 32d = 968 ...(2)

Now, from equation (2) we get,

a + 32d = 968

a + 18d + 14d = 968

548 + 14d = 968 (.°. <u>a + 18d = 548</u>)

14d = 968 - 548

14d = 420

d = 420 ÷ 14

d = 30

Now, for the value of a put the value of d = 30 in equation (1)

a + 18d = 548

a + 18(30) = 548

a + 540 = 548

a = 548 - 540

a = 8

Now, For a₂₇

a₂₇ = a + 26d

a₂₇ = 8 + 26(30)

a₂₇ = 8 + 780

a₂₇ = 788

Thus, The value of a₂₇ is 788

<u>-TheUnknownScientist</u>

4 0
3 years ago
Drag an answer to each box to complete this paragraph proof.
sveticcg [70]

1.) m∠P+m∠Q+m∠R=180

2.) x=10


4 0
3 years ago
Read 2 more answers
among 210 student 85 price in English 125 price in Nepali and 25 failed in both subject find the number of students who passed i
notka56 [123]

Answer:

210=85+125-x+25

x= 235-210

x=25 failled in both

Step-by-step explanation:

5 0
3 years ago
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