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Irina-Kira [14]
3 years ago
5

Y 2 + 5y Choose the constant term that completes the perfect square trinomial.

Mathematics
1 answer:
mafiozo [28]3 years ago
7 0
Given: y²+5y
Converting y²+5y in the form: x²+2ax+a²
Here 2a=5 or a=5/2
Add and subtract (5/2)²
y²+5y+(5/2)²-(5/2)²   
Complete the square.
(y+5/2)²-(5/2)²
Simplify
(y+5/2)² - 25/4

Answer: (y+5/2)² - 25/4

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Every two years, there is a local election in a small town. In 2015, a total of 29,000 voters turned out in the election. In 201
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Answer:

29730 voters

Step-by-step explanation:

so:

in 2017- 16/100=0.16 x 29,000=4640 so 29,000-4640=24360 voters

in 2019-22/100=0.22 x 24369=5361.18 so 24369+5361.18=29730.18 voters

I hope this helped

4 0
3 years ago
If Zach has 4 times as many nickels as quarters and they have a combined value of 360 cents, how
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5 Dimes and 20 Quarters

Step-by-step explanation:

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Trisha is selling lemonade at a fundraiser she bought 2 bag of cups each bag contained 90 cups and cost 3.60.The total cost of t
timama [110]

yes she made profit

2x90=180

180x0.50=90

she made $90 and only had to pay $3.60

7 0
3 years ago
PLS HELP!!!<br> Evaluate.<br> 4^3−4÷2⋅5
Snowcat [4.5K]

Answer:

62.4

Step-by-step explanation:

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3 years ago
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Here is 3 &amp; 4 I NEED DONE ASAP!
Marrrta [24]

Given matrices are from here

brainly.com/question/18267865

=====================================================

Problem 3

a)

B - C = DNE

We cannot subtract matrices of different sizes. Matrix B is 2x2 while C is 3x2. Both matrices must have the same number of rows, and they must also have the same number of columns. The matrices don't have to be square.

------------------------------

b)

A+B = \begin{bmatrix}-5 & 6\\7 & 4\end{bmatrix}

You add the corresponding elements. For instance, in the top left corner we have -1+(-4) = -5. The other entries are treated in a similar manner.

------------------------------

c)

-2E = \begin{bmatrix}6 & -4 & 8\\-12 & 14 & -16\\-10 & -18 & 20\end{bmatrix}

You get this from multiplying each entry in matrix E by -2. Eg: top left corner has -2*(-3) = 6

------------------------------

d)

CD = \begin{bmatrix}4 & 7 & 8\\ 1 & 3 & 4\\14 & 17 & 16\end{bmatrix}

Matrix C has 3 rows and D has 3 columns. The final answer will be size 3x3

To generate each value in the answer matrix, you'll highlight rows of C to pair with columns of D. Then you'll multiply out the corresponding values, after which you add those products. This is done for every entry in the answer shown above.

For example, the first row of C is highlighted and the second column of D is highlighted. Those values pair up and multiply getting -1*(-1) + 2*3 = 1+6 = 7, which goes in the first row and second column of the answer matrix. The other entries are handled in a similar fashion.

------------------------------

e)

\det(B) = -46

The 2x2 matrix determinant formula is \begin{vmatrix}a & b\\c & d\end{vmatrix} = a*d - b*c

In this case, a = -4, b = 6, c = 5, d = 4.

------------------------------

f)

B^{-1} = \begin{bmatrix}-2/23 & 3/23\\ 5/46 & 2/23\end{bmatrix}

Swap the top left and bottom right corners of matrix B. Change the sign of the other two corner values. Then multiply each entry by 1/d where d is the determinant found back in part (e) above. Be sure to reduce any fraction as much as possible.

=====================================================

Problem 4

Answers: x = 2  and y = -10

-----------------

Work Shown:

\begin{bmatrix}2x & 4\\-5 & -2\end{bmatrix}+\begin{bmatrix}3 & -7\\11 & y-1\end{bmatrix} = \begin{bmatrix}7 & -3\\6 & -13\end{bmatrix}\\\\\\\begin{bmatrix}2x+3 & 4+(-7)\\-5+11 & -2+(y-1)\end{bmatrix} = \begin{bmatrix}7 & -3\\6 & -13\end{bmatrix}\\\\\\\begin{bmatrix}2x+3 & -3\\6 & y-3\end{bmatrix} = \begin{bmatrix}7 & -3\\6 & -13\end{bmatrix}\\\\\\

In the top left corners of each matrix, in line 3, we have 2x+3 = 7 which solves to...

2x+3 = 7

2x = 7-3

2x = 4

x = 4/2

x = 2

In the bottom right corners, we have y-3 = -13 which solves to....

y-3 = -13

y = -13+3

y = -10

4 0
4 years ago
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