Let width of rectangle be "x"
L= 3x W=x
if width is diminished by 1 that means new width = (x-1)
similarly the new length would be (3x+3)
hence (x-1)*(3x+3)=72
(3x^2)-3=72
3x^2=75
x^2=25
x= +/- 5
reject -5 as you cant have negative length
hence x=5
so original dimensions of rectangle is
L= 15m W=5m
Answer:
The answer would be 17
Step-by-step explanation:
The answer would be 17 because if you add 12 plus 5 That would be your answer
Hello,
A(x)=x²-x-72 (m²)
L=(x+8) (cm)= (x+8)/100 (m)
We suppose here x≠-8
(in reality x²-x-72>0 ==>x<-8 or x>9
but x+8>0 ==> x>-8
then
only x>9 are solutions)
W=A(x)/ ((x+8)/100 )=100*(x²-x-72)/(x+8)= 100*(x-9)(x+8)/(x+8)=100*(x-9)
Answer:
11 /13 = t
Step-by-step explanation:
5/13 = t -6/13
Add 6/13 to each side
5/13 + 6/13 = t -6/13+ 6/13
11 /13 = t
C = 2πr Divide both sides by 2π
C/2π = r Switch the sides to make it easier to read
r = c / 2π
