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3 years ago

Which of the following proportions is TRUE? a. 1:4 = 2:5 b. 6:9 = 10:12 c. 5:11 = 15:30 d. 2:7 = 4:14

Mathematics

1 answer:

Vlad1618 [11]3 years ago

5 0

2:7 = 4:14 because each is equal to 2/7. If you simplify 4:14 by dividing by 2, it simplifies to 2:7.

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ACFG is a parallelogram, If AX = 4y + 3 and XF = 2y + 7, find AX.

pashok25 [27]

Answer:

AX=XF

4y+3=2y+7

4y-2y=7-3

2y=4

y=2

then,

AX=4y+3

=4×2+3

=8+3

=11

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2 years ago

Can you guys teach me how to do this??

Vadim26 [7]

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3 years ago

(5j - 2q + 2/5) - (4 - 3j - 1/2q)

fenix001 [56]

Answer:

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Step-by-step explanation:

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2 years ago

How do I simplify this radical?

Yuliya22 [10]

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3 years ago

A school wants to put on a dance recital Middle School dancers have short programs that run 4 minutes long High School performer

sp2606 [1]

Answer: The answer is $\textup{M}+\textup{H}\leq 10~~\textup{and}4\textup{M}+7\textup{H}\leq 90.$

Step-by-step explanation: Given that a school wants to put on a dance recital. The programs of Middle school dancer will be short of 4 minutes each and programmes of High school performers will be long of 7 minutes each.

Number of middle school dances is "M" and number od high school dances is "H".

Since there cannot be more than 10 dances all together, so fisrt inequality can be written as

$\textup{M}+\textup{H}\leq 10.$

Also, the entire recital must take maximum 90 minutes, so the second inequality can be written as

$4\textup{M}+7\textup{H}\leq 90.$

Thus, the pair of inequalities is

$\textup{M}+\textup{H}\leq 10,\\\\4\textup{M}+7\textup{H}\leq 90.$

6 0

2 years ago