Answer:
Step-by-step explanation:
LOL get some fidgets or a stress ball. they help
The substitution method means you replace the variable in one equation with the other equation, so your new equation is x+4x-8=10. Add 10 to both sides to get 5x=18. Divide both sides by 5 to get x=3.6. This is a weird equation, but then to get y, work backwords. 3.6 times 2=7.2. 7.2-4=3.2 y=3.2. Finally to finish checking solve the equation as normal. 3.6+6.4=10. I hope this helped! Please give brainliest!
Your final answer is x=3.6 y=3.2
It is a prime because the only other factor of 6w^3-13 is 1.
Answer:
4-
30 minutes --- 562.5 miles
240 minutes --- 300 miles
480 minutes --- 0 miles
600 minutes --- 150 negative miles (they would have already arrived).
5- 240 CDs will weigh 720 ounces.
Step-by-step explanation:
4- Given that Bryan family's summer house is 600 miles away, and after 30 minutes, they are 562.5 miles left to their destination, to determine the distance in the following minutes the following calculations must be performed:
30 minutes --- 562.5 miles
240 minutes --- 300 miles
600 - 562.5 = (37.5) / 30 = (1.25) x 240 = 300 miles
480 minutes --- 0 miles
600 - 562.5 = (37.5) / 30 = (1.25) x 480 = 600 miles
600 minutes --- 150 negative miles
600 - 562.5 = (37.5) / 30 = (1.25) x 600 = 750 miles
5- Given that Jasmine mails 2 CDs in an envelope and the envelope weighs 6 ounces, to calculate the weight of 240 CDs the following algebraic calculation must be performed:
6/2 x 240 = X
3 x 240 = X
720 = X
Thus, 240 CDs will weigh 720 ounces.
Number of apples purchased = A
Cost of each apple = 15 cents
Then
The total cost of 15 apples = 15A
Number of bananas purchased = B
Cost of each banana = 10 cents
Then
Cost of 10 bananas = 10B
So
The total value of purchase = 15A + 10B
So the correct option among all the options given in the question is option "D",. I hope the procedure is clear enough for you to understand. Using this procedure it will be possible for you to answer similar questions with ease and without requiring any help from outside.