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Feliz [49]
2 years ago
5

I need some help on these 3 questions :)

Mathematics
1 answer:
wlad13 [49]2 years ago
3 0

The factor of the polynomial, the area of the pool and the simplified expression are all algebraic expressions

<h3>How to simplify the expressions?</h3>

<u>Factor of the polynomial</u>

The polynomial is given as:

2x^3 + 6x^2 + 6x + 18

Factor out 2

2x^3 + 6x^2 + 6x + 18 = 2(x^3 + 3x^2 + 3x + 9)

Factorize

2x^3 + 6x^2 + 6x + 18 = 2(x^2(x + 3) + 3(x + 3))

Factor out x + 3

2x^3 + 6x^2 + 6x + 18 = 2(x^2 + 3)(x + 3)

Expand

2x^3 + 6x^2 + 6x + 18 = (2x^2 + 6)(x + 3)

Hence, 2x^2 + 6 is a factor of the polynomial 2x^3 + 6x^2 + 6x + 18

<u>The length of the pool</u>

The given parameters are:

Area = 2x^3 - 29x + 12

Width = x + 4

The length is calculated as:

Length = Area/Width

This gives

Length = 2x^2 - 29x + 12/x + 4

Factorize the numerator

Length = (2x^2 - 8x + 3)(x + 4)/x + 4

Cancel out x + 4

Length = 2x^2 - 8x + 3

Hence, the length of the pool is 2x^2 - 8x + 3

<u>Simplify the expression</u>

The expression is given as:

(3s^2 - 2s + 1) \div (s^2 - s + 2)

Evaluate the quotient

3 + (s - 5)/(s^2 - 5 + 2)

Hence, the simplified expression is 3 + (s - 5)/(s^2 - 5 + 2)

Read more about algebraic expressions at:

brainly.com/question/2164351

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Jessie is fencing in a rectangular plot outside of her back door so that she can let her dogs out to play. She has 60 feet of fe
DerKrebs [107]

Answer:

Dimensions are length 15 feet and width 30 feet.

Maximum area of the plot is 450 feet².

Step-by-step explanation:

Let the length of the plot = x feet and width = y feet.

Since, the amount of fencing to be applied on the three sides of the plot is 60 feet.

We have,

2x + y = 60 i.e. y=60-2x

Now, Area of the rectangular plot = Length × Width

i.e. Area of the rectangular plot = x \times y

i.e. Area of the rectangular plot = x\times (60-2x)

i.e. Area of the rectangular plot = -2x^2+60x

<em>Since, the maximum of the quadratic equation ax^2+bx+c will be obtained at x= \frac{-b}{2a}.</em>

Then, the maximum of the area of the plot is at the point x= \frac{-60}{2\times (-2)} i.e. x= 15

Then, maximum area of the rectangular plot = -2x^2+60x

i.e. maximum area of the rectangular plot = -2\times 15^2+60\times 15

i.e. maximum area of the rectangular plot = -450+900 = 450 feet²

Hence, Maximum area of the plot is 450 feet².

Then,y=60-2\times 15 implies y=60-30 i.e. y= 30.

Hence, the maximum area is enclosed by the length 15 feet and width 30 feet.

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3 years ago
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