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ivanzaharov [21]
2 years ago
11

PLEASE ANSWER THE QUESTION IN THE PICTURE BELOW

Mathematics
1 answer:
vekshin12 years ago
8 0

9514 1404 393

Answer:

  12 square inches

Step-by-step explanation:

The area is given by the formula ...

  A = 1/2bh

Here, the base is 6 inches and the height is given as 4 inches. Then the area is ...

  A = (1/2)(6 in)(4 in) = 12 in²

The area of the triangle is 12 square inches.

_____

<em>Comment on the problem</em>

Since you are given the base and height, we presume you are intended to use the formula above. You are also given all three side lengths. If you use the appropriate formula with those, you find the area is about 15.6 square inches. (The height of this triangle is actually closer to 5.2 inches.)

The figure represents a geometry that cannot exist. With the given base and height, the side lengths should be 5, not 6.

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If a and b are odd integers, then a – b is an even integer.
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So the answer choices are
1. a-b=even
2. a and b are not odd
3. a and b are odd
4. a-b=even
5. a-b=not even

even=not odd
not even=odd so choice 5 is really a-b=odd
basically choice 4 and 1 are the same so we cross one out
so
the problem said that a and b are odd so therefor choice2 is wrong and choice 3 is correct

then both are odd
odd-odd=even because
an even number is represented as 2n where n is an integer
an odd number can be represented as 2n+1 so assume you have 2 odd numbers 2 away from each other so odd and (odd+2)
odd+2-odd=2n+1+2-(2n+1)=2n+1+2-2n-1=2n-2n+1-1+2=2
you are left with odd
using integers
7 and 11
11-7=4
even

so odd-odd=even, it depends on weather you consider 0 odd or even


so the asnwers are:
a and b are odd
a-b is not an even integer
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