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aev [14]
4 years ago
14

How to simplify this question

Mathematics
1 answer:
ANEK [815]4 years ago
6 0
Simplification = 3.5x + 2.5x
Result = 6x
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Decide which chi-square test (goodness-of fit, homogeneity, or independence) would be most appropriate for the given situation.
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Answer:

C. Test for Goodness-of-fit.

Step-by-step explanation:

C. Test for Goodness-of-fit would be most appropriate for the given situation.

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The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.

B. Test for Independence.

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C. Test for Goodness-of-fit.

The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with  their estimates and provided that one degree of freedom is deducted for each parameter estimated.

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3 years ago
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Elena-2011 [213]
We can express it at 5 (a+6)
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Triangle KJL is inscribed in semicircle O shown below such that JK=6 and JL=11. Which of the following is closest to the radius
lakkis [162]

Uhh, answer choices?

In any case, since \triangle KJL is inscribed in a semicircle, it is a right triangle (due to the inscribed angle theorem). Thus, by the Pythagorean theorem, KL=\sqrt{6^2+11^2}=\sqrt{157}. Now, the circumradius of a right triangle (the radius of the circle passing through all three of its vertices) is simply half its hypotenuse, so OJ=OK=OL=\frac{\sqrt{157}}{2}\approx \boxed{6.265}.

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