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Lubov Fominskaja [6]
3 years ago
14

Given the equation f(x) = 2x² + 4x - 1, what is axis of symmetry? a. 1 c. -1 b. 2 d. 0

Mathematics
1 answer:
Irina-Kira [14]3 years ago
4 0

Answer: x=-1

Step-by-step explanation:

the x value of the vertex = -b/2a if the equation is in "ax^2+bx+c" for

you are in luck

x value of the vertex = -4/4 = -1

the line of symmetry is a vertical line, and since it must pass through the vertex

line of symmetry: x=-1

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Tim has a large collection of books. The number of paperback books he owns is three less then four times the number of hardcover
dlinn [17]

Answer: let the no of paperback books be x and hardcover books be y

4y - x = 3

Therefore, x - 4y = -3 -----(1)

x + y = 447 ----(2)

Put x = 447 - y in eqn 1

447- y - 4y = -3

-5y = -3 - 447

-5y = -450

y = 90

x = 357

Step-by-step explanation:

3 0
3 years ago
Combine like terms<br> 9(x - y) +3 – 4y + x
Phantasy [73]

Answer:

10x-13y+3

Step-by-step explanation:

first distribute the 9 to the (x-y) and you get

9x-9y+3-4y+x then combine like terms so

10x-13y+3

4 0
3 years ago
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Gloria is trying to save for retirement. She deposits $200 each month for 20 years into an account that pays 4.2% compounded int
AURORKA [14]
B is the correct answer.
6 0
4 years ago
An article in Technometrics (Vol. 19, 1977, p. 425) presents the following data on the motor fuel octane ratings of several blen
Slav-nsk [51]

Answer:

Median = 90.4

Q_1 = 88.6

Q_3 = 92.2

Step-by-step explanation:

Given

The above data

Required

- A stem and leaf display

- The median

- The quartiles

First, determine the range of the data

Smallest = 83.4

Highest = 100.3

Next, group each dataset base on common whole numbers.

So, we have:

83.4

84.3\ 84.3

85.3

86.7\ 86.7\ 86.7

87.4\ 87.5\ 87.6\ 87.7\ 87.8\ 87.9

88.2\ 88.3\ 88.3\ 88.3\ 88.4\ 88.5\ 88.5\ 88.6\ 88.6\ 88.7\ 88.9

89.0\ 89.2\ 89.3\ 89.3\ 89.6\ 89.7\ 89.8\ 89.8\ 89.9\ 89.9

90.0\ 90.1\ 90.1\ 90.1\ 90.3\ 90.4\ 90.4\ 90.4\ 90.5\ 90.6\ 90.7\ 90.8\ 90.9

91.0\ 91.0\ 91.0\ 91.1\ 91.1\ 91.1\ 91.2\ 91.2\ 91.2\ \ 91.5\  91.6\ 91.6\ 91.8\ 91.8

92.2\ 92.2\ 92.2\ 92.3\ 92.6\ 92.7\ 92.7\ 92.7

93.0\ 93.2\ 93.3\ 93.3\ 93.4\ 93.7

94.2\ 94.2\ 94.4\ 94.7

96.1\ 96.5

98.8

100.3

Next, we construct the stem and leaf plot.

The whole numbers will be the stem while the decimal parts will be the leaf.

So, we have:

\begin{array}{ccc}{Stem} & {} & {Leaf} & {83} & {|} & {.4} & {84} & {|} & {.3\ .3} & {85} & {|} & {.3} & {86} & {|} & {.7\ .7\ .7} & {87} &{|} & {.4\ .5\ .6\ .7\ .8\ .9} & {88} & {|} & {.2\ .3\ .3\ .3\ .4\ .5\ .5\ .6\ .6\ .7\ .9} &{89} & {|} & {.0\ .2\ .3\ .3\ .6\ .7\ .8\ .8\ .9\ .9} & {90} & {|} &{.0\ .1\ .1\ .1\ .3\ .4\ .4\ .4\ .5\ .6\ .7\ .8\ .9} & {91} &{|}&{.0\ .0\ .0\ .1\ .1\ .1\ .2\ .2\ .2\ .5\ .6\ .6\ .8\ .8} &{92} &{|} &{.2\ .2\ .2\ .3\ .6\ .7\ .7\ .7} \ \end{array}

  \begin{array}{ccc} {93} & {|} & {.0\ .2\ .3\ .3\ .4\ .7} & {94} &{|} & {.2\ .2\ .4\ .7} &{96} & {|} & {.1\ .5} & {98} & {|} & {.8} & {100} &{|} &{.3} \ \end{array}

From the above plot,

n = 83

The median is calculated as:

Median = \frac{n+1}{2}th

Median = \frac{83+1}{2}th

Median = \frac{84}{2}th

Median = 42nd

i.e. the median is at the 42nd position.

From the above stem and leaf plot.

The 42nd position is at stem 90 and the leaf  .4

So the median is:

Median = 90.4

The lower quartile (Q) is calculated as:

Q_1 = \frac{n+1}{4}th

Q_1 = \frac{83+1}{4}th

Q_1 = \frac{84}{4}th

Q_1 = 21st

i.e. the lower quartile is at the 21st position.

From the above stem and leaf plot.

The 42nd position is at stem 88 and the leaf .6

So the lower quartile is:

Q_1 = 88.6

The upper quartile (Q3) is calculated as:

Q_3 = 3 * \frac{n+1}{4}th

Q_3 = 3 * \frac{83+1}{4}th

Q_3 = 3 * \frac{84}{4}th

Q_3 = 3 * 21th

Q_3 = 63rd

i.e. the upper quartile is at the 63rd position.

From the above stem and leaf plot.

The 63rd position is at stem 92 and the leaf .2

So the upper quartile is:

Q_3 = 92.2

8 0
3 years ago
Find all values of c such that f is continuous on (-[infinity], [infinity]). f(x) = { 3 - x^2 x less than or equal to c x, x &gt
yuradex [85]

Answer:

a) c=\frac{-1+\sqrt{13}}{2} and c=\frac{-1-\sqrt{13}}{2}

Step-by-step explanation:

The idea for the solution of this equation is to find the value of c where both parts of the piecewise-defined function are the same. So we need to take the parts of the function and set them equal to each other, so we get:

3-x^{2}=x

and then solve for x. We move everything to one side of the equation so we get:

x^{2}+x-3=0

and we use the quadratic formula:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

and we substitute:

x=\frac{-1\pm \sqrt{(1)^2-4(1)(-3)}}{2(1)}

and solve

x=\frac{-1\pm \sqrt{1+12}}{2}

x=\frac{-1\pm \sqrt{13}}{2}

so our two answers are:

a) c=\frac{-1+\sqrt{13}}{2} and c=\frac{-1-\sqrt{13}}{2}

6 0
3 years ago
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