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olganol [36]
3 years ago
14

Y+x=1 show whether x and y show direct variation ​plzz helpp

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
7 0

Answer:

No

Step-by-step explanation:

Please write:  "Determine whether y+x=1 shows direct variation."

No, it does not, because of the constant term, 1.

If we were to eliminate the 1 and write y + x = 0, then yes, this would represent direct variation.

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A radius is a segment that connects any point on the circle to the center of that circle
jok3333 [9.3K]

Answer:

Yeah

Step-by-step explanation:

I don't what is the question here but yeah. Radious is also half of diameter.

3 0
3 years ago
Plss help me as soon as possible i will give you lots of points
mezya [45]

Answer:

Step-by-step explanation:

75x + -300 = 25x + 200

Reorder the terms:

-300 + 75x = 25x + 200

Reorder the terms:

-300 + 75x = 200 + 25x

Solving

-300 + 75x = 200 + 25x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-25x' to each side of the equation.

-300 + 75x + -25x = 200 + 25x + -25x

Combine like terms: 75x + -25x = 50x

-300 + 50x = 200 + 25x + -25x

Combine like terms: 25x + -25x = 0

-300 + 50x = 200 + 0

-300 + 50x = 200

Add '300' to each side of the equation.

-300 + 300 + 50x = 200 + 300

Combine like terms: -300 + 300 = 0

0 + 50x = 200 + 300

50x = 200 + 300

Combine like terms: 200 + 300 = 500

50x = 500

Divide each side by '50'.

x = 10

Simplifying

x = 10

3 0
3 years ago
A bookshelf is 14 inches wide there is enough space to fit 3 trophies one trophy is 2 inches wider than the other how wide is th
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8 0
3 years ago
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What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1
Ratling [72]

Answer:

\sqrt3

Step-by-step explanation:

To find:

The value of tan60^\circ = ?

Solution:

Kindly consider the equilateral \triangle ABC as attached in the answer area.

Let the side of triangle = a units

Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = \frac{a}{2}

Using Pythagorean Theorem in \triangle ABD:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}

Side AD = \frac{\sqrt3}{2}a

Using Trigonometric ratio:

tan\theta = \dfrac{Perpendicular}{Base}

tanB = \dfrac{AD}{BD}

Putting the values of AD and BD:

tan60^\circ=\dfrac{\frac{\sqrt3}{2}a}{\frac{1}{2}a}\\\Rightarrow tan60^\circ = \bold{\sqrt3}

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erma4kov [3.2K]

Answer:

I think its D sorry if I get it wrong

Step-by-step explanation:

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