I need help with 1 and 2

Mathematics

1 answer:

Solnce55 [7]2 years ago

5 0

Answer:

1. B, C 2.RSQ=53

Step-by-step explanation:

1. 7x-34+2(4x+2)=180

x=14

4(14)+2=58

180-58=122

2. 180-74 =106

106/2 = 53

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33% of what number is 1.45? Round to the nearest tenth.

tatuchka [14]

Take the unknown number as 'y'.

=》33% = 33/100

=》1.45 = 145/100

33/100 × y = 1.45

33/100 × y = 145/100

33y = 145/100 × 100/1

33y = 145

y = 145/33

y = 4.39

______

RainbowSalt2222 ☔

3 0

3 years ago

Read 2 more answers

Help I am very bad at math I need answers by tomorrow if you can help please do

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

= Cosec² A + Cosec² A - 1

= 2Cosec² A - 1 = RHS

$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$