(Distribute the minus sign of the subtrahend in each term.)
= 8r⁶s³ – 9r⁵s⁴ + 3r⁴s⁵ – 2r⁴s⁵ + 5r³s⁶ + 4r⁵s⁴
(Add or subtract like terms.)
= 8r⁶s³ – 5r⁵s⁴ + r⁴s⁵ + 5r³s⁶
(If you want to factor out, then...)
= r³s³ (8r³ – 5r²s + rs² + 5s³)
Answer:
-14
Step-by-step explanation:
First of all, we know that 5x^2+ ax+7x +5=0 only has one root. That means that b^2 - 4ac=0, and we can use this to find the discriminant, ax + 7x.
Now, if we simplified 5x^2+ ax+7x +5=0, by dividing it all by 5, it would be x^2+(a+7)/5x + 1 = 0.
After, we can plug what we know into the formula, b^2 - 4ac=0. It would be:
(a+7)^2 / 25 - 4 = 0
(a+7)^2 / 25 = 4
(a+7)^2 = 100
Since this is a square root, a+7 can be both negative or positive.
a+7= 10, or a+7 = -10
a=3, or a=-17
The question asks for the sum of a, which is 3 + (-17) = -14
Therefore, the answer is -14.
:) have fun with your rsm problems, assuming you got this from the portal.
Answer:
x<8
Step-by-step explanation:
2x+5>3x-3
2x+8>3x
8>x
Number of tickets= X
To find the number of tickets, divide the money Jan has with the cost of each ticket.
So,
X =37.50/ 5.25=7.14
But since she can't buy part of a ticket, Jan can buy 7 tickets
