14a^2bc^4/21abc^6 = 2a/3b^2
Answer:
- Exact distance =
feet - Approximate distance = 127.2792 feet.
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Explanation:
The area of the square is 8100 square feet, abbreviated ft^2.
Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.
If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).
Use the pythagorean theorem to find the hypotenuse.

The distance from 1st to 3rd base is roughly 127.2792 feet.
Answer:
yes
Step-by-step explanation:
Answer:
B. 
Step-by-step explanation:
Simplify the expression. Remember to go by the order of operations, or PEMDAS.
1) First, distribute the numbers outside of the set of parentheses to the terms inside the set of parentheses next to them. Then, simplify the fractions.



2) Finally, combine like terms. (This means to add or subtract constants and to add or subtract terms with the same variables.) You may need to convert terms to the same denominator in order to do so easier. Then, reduce the fraction.

Thus, the answer is
.