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4 years ago

14

Write an equation that describes the line that passes through (2, 2) and (0, -3).

1 answer:

gtnhenbr [62]4 years ago

5 0

Answer:

f(x) = $\frac{5}{2}$ x

Step-by-step explanation:

The first thing we need to find is the slope of the line able to pass through the given two points. Right now we have <em>y = mx + b</em> (linear function equation) and we need to find <em>m</em>.

Using the slope formula or $m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}$ and plugging in the given points' x and y values:

$\frac{-3-2}{0-2}$ = $\frac{-5}{-2}$ = $\frac{5}{2}$

The slope of the line is that for every 5 units the line goes upwards, it goes 2 units to the right.

Our equation is now <em>y = $\frac{5}{2}$ x + b</em>. If you were in need of it, <em>b </em>gives the line's y-intercept, the place where it hits the y-axis. In this case you do not need <em>b</em> because the only specified conditions in the problem are the units the line hits.

Our final equation is:

f(x) = $\frac{5}{2}$ x

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