Answer:
45 g of the solid Tris will be dissolved in 2.5 liters of water.
Explanation:
Recall that:
<em>Number of moles = molarity x volume</em>
Hence, number of moles of Tris present in 2.5 liters, 150 mM solution:
= 150/1000 x 2.5 = 0.375 moles
Also, recall that:
<em>No of moles of substance = mass/molar mass.</em>
Hence, mass of 0.375 moles substance:
= no of moles of the substance x molar mass of the substance.
= 0.375 x 120 = 45 g.
Therefore, in order to prepare 2.5 liters, 150 mM of an aqueous solution of Tris, 45 g of the solid Tris will be dissolved in 2.5 liters of water.
Bases wich combine in groups of two to create base pairs
Osmosis is the movement from high to low concentrations with no energy
Answer:
B. The heart beat and pulse rate may change, but are always equal.
Hope this helps :D Have a fantastic day
