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fgiga [73]
4 years ago
15

the average white rhinoceros gives birth to a single calf that weighs about 3.8% as much as its mother. if the mother rhinoceros

weighs 3.75 tons, about how many pounds does its calf weigh?
Mathematics
2 answers:
Lisa [10]4 years ago
7 0
Here is the solution of the given problem above.
Given: Weight of single calf = weight of mother + 3.8%
           Weight of mother = 3.75 tons or 7,500 pounds
           ? = weight of the calf
First, we need to find the 3.8% of 7,500 pounds. The result is 285 pounds.
So to get the weight of the calf, let's add 7,500 pounds to 285 pounds and the result is 7,785 pounds. So the weight of the calf is 7,785 pounds. Hope this helps.
seropon [69]4 years ago
6 0

Answer:   285\text{ pounds}

Step-by-step explanation:

Given :The average white rhinoceros gives birth to a single calf that weighs about 3.8% as much as its mother.

We can convert percent into decimal by dividing it by 100.

Thus , 3.8% will become 0.038.

If the mother rhinoceros weighs 3.75 tons, then the number of pounds its calf weigh is given by :-

0.038\times3.75=0.1425\text{ tons}

We know that 1 ton = 2000 pounds

Then, Weight of calf = 0.1425\times2000=285\text{ pounds}

Hence, the required answer is 285\text{ pounds} .

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Answer:

Coordinates of point B are (10,-4)

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Step-by-step explanation:

1) Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are ____

Let the coordinates of B be (x_2,y_2)

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Coordinates of B = (10,-4)

2)If point D divides in the ratio 4 : 5, the coordinates of point D are ____

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We will use section formula over here

x=\frac{mx_2+nx_1}{m+n} , y = \frac{my_2+ny_1}{m+n}

m:n=3:2

x=\frac{3(10)+2(-6)}{3+2} , y=\frac{3(-4)+2(5)}{3+2}\\x=3.6,y=-0.4

Coordinates of point B are (10,-4)

Coordinates of point D are (3.6,-0.4)

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