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Lana71 [14]
2 years ago
5

Can somebody help me out please !

Mathematics
1 answer:
ivann1987 [24]2 years ago
5 0

Answer:

d i think maybe i dont know if im rong ask some one else

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5(x-8)=30<br> WILL GIVE BRAINLIST AND THANKS IF CORRECT
zvonat [6]

Answer:

x = 14

Step-by-step explanation:

5x - 40 = 30

+40       +40

5x   = 70

divide by 5 on both sides

x= 14

7 0
3 years ago
What is the slope of the line passing through the points ( 1, 5/7) and (2,2/7)
marshall27 [118]
Answer:

2/7-5/7=-3/7
2-1= 1

y=-3/7x
8 0
3 years ago
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1,170,000,000 in scientific notation
ki77a [65]
Here you go <span> 1.17 × 10^</span><span>9


</span>
6 0
3 years ago
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Calculus 2 master needed; evaluate the integral PLEASE SHOW STEPS IF IM WRONG <img src="https://tex.z-dn.net/?f=%5Cint%7Bsin%5E3
sweet [91]

Answer:

Yes, you answer is correct! It just needs to be simplified :)

Step-by-step explanation:

So we have the integral:

\int \frac{\sin^3(x)}{\sqrt{\cos(x)}}dx

As you had done, we can split off the numerator:

=\int \frac{\sin(x)(\sin^2(x))}{\sqrt{\cos(x)}}dx

Using the Pythagorean Identity, this is:

=\int \frac{\sin(x)(1-\cos^2(x))}{\sqrt{\cos(x)}}dx

Now, we can do u-substitution. Let u equal cos(x). Thus:

u=\cos(x)\\du=-\sin(x)dx\\-du=\sin(x)dx

So:

=\int \frac{1-u^2}{\sqrt{u}}(-du)

Simplify:

=-\int\frac{1-u^2}{\sqrt u}du

We can then split the terms:

=-\int \frac{1}{\sqrt u}-\frac{u^2}{\sqrt u}du

Expand the integral:

=-(\int \frac{1}{\sqrt u}du-\int\frac{u^2}{\sqrt u}du)

Simplify each of the u.

For the left, that is simply u^-1/2.

For the right, it is u^(2-1/2) or u^3/2. Thus:

=-(\int u^{-\frac{1}{2}}du-\int u^{\frac{3}{2}}du)

Reverse Power Rule:

=-(\frac{u^{1+-\frac{1}{2}}}{1+-\frac{1}{2}}-\frac{u^{1+\frac{3}{2}}}{1+\frac{3}{2}})

Simplify:

=-(\frac{u^{\frac{1}{2}}}{\frac{1}{2}}-\frac{u^{\frac{5}{2}}}{\frac{5}{2}})

Simplify further:

=-(2u^{\frac{1}{2}}-\frac{2u^{\frac{5}{2}}}{5})

Distribute the negative:

=-2u^{\frac{1}{2}}+\frac{2u^{\frac{5}{2}}}{5}

And substitute back cos(x) for u:

=-2\cos^{\frac{1}{2}}(x)+\frac{2\cos^{\frac{5}{2}}(x)}{5}

And this is precisely what you got, so well done!

We can simplify this by first multiplying the first term by 5 to get a common denominator. So:

=-\frac{10\cos^{\frac{1}{2}}(x)}{5}+\frac{2\cos^{\frac{5}{2}}(x)}{5}

Combine:

=\frac{-10\cos^{\frac{1}{2}}(x)+2\cos^{\frac{5}{2}}(x)}{5}

Factor out a cos^(1/2)(x) and a 2. Since we factored out a cos^(1/2)(x), we need to subtract their exponents inside. Thus:

=\frac{2\cos^{\frac{1}{2}}(x)(-5\cos^{\frac{1}{2}-\frac{1}{2}}(x)+\cos^{\frac{5}{2}-\frac{1}{2}}(x))}{5}

Simplify:

=\frac{2\cos^{\frac{1}{2}}(x)(-5+\cos^2(x))}{5}

Simplify:

=\frac{2\sqrt{\cos{x}}(\cos^2(x)-5)}{5}

And, of course, C:

=\frac{2\sqrt{\cos{x}}(\cos^2(x)-5)}{5}+C

So:

\int \frac{\sin^3(x)}{\sqrt{\cos(x)}}dx=\frac{2\sqrt{\cos{x}}(\cos^2(x)-5)}{5}+C

And we're done :)

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3 years ago
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Which graph shows the solution set for -4.4 &gt; (or equal to) 1.6x - 3.6
7nadin3 [17]

B

<--|-----|-----|------|------|

  -7           -6           -5

5 0
3 years ago
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