In order to at least earn $90, Katie can work exercising horses for 6 hours and cleaning stalls for 6 hours.
Step-by-step explanation:
Let hours of exercising horses be x --> $5 per hour = 5x
Let hours of cleaning stalls be y --> $10 per hour = 10y
Total earning = 
Total hours = 12
<u>Equation 1:</u>
5x + 10y =
<u>Equation 2:</u>
x + y 
<em>1. Multiply equation 2 by -5</em>
x + y (*-5)
5x + 10y =
-5x - 5y 
5x + 10y =
<em>2. Solve</em>
-5x + 5x -5y + 10y = -60 + 90
5y = 30
y = 6
x + y = 12
x + 6 = 12
x = 6
Therefore, in order to at least earn $90, Katie can work exercising horses for 6 hours and cleaning stalls for 6 hours.
Keywords: Simultaneous, hours, equations
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Out of numbers: 5, 7, 21, 25, 28, 35, 42, 56, 75, and 80, choose those which are not factors of 42
Blizzard [7]
Answer:
5, 25, 28, 35, 56, 75 80 are not the factors of 42
The answer is (1/2)xe^(2x) - (1/4)e^(2x) + C
Solution:
Since our given integrand is the product of the functions x and e^(2x), we can use the formula for integration by parts by choosing
u = x
dv/dx = e^(2x)
By differentiating u, we get
du/dx= 1
By integrating dv/dx= e^(2x), we have
v =∫e^(2x) dx = (1/2)e^(2x)
Then we substitute these values to the integration by parts formula:
∫ u(dv/dx) dx = uv −∫ v(du/dx) dx
∫ x e^(2x) dx = (x) (1/2)e^(2x) - ∫ ((1/2) e^(2x)) (1) dx
= (1/2)xe^(2x) - (1/2)∫[e^(2x)] dx
= (1/2)xe^(2x) - (1/2) (1/2)e^(2x) + C
where c is the constant of integration.
Therefore,
∫ x e^(2x) dx = (1/2)xe^(2x) - (1/4)e^(2x) + C
-9/14 4/14 now you have the same denominator so you can add
-9 + 4 = -5
-5/14
Answer:
The answer is C
Step-by-step explanation:
Hope this helps.
