For this case, the first thing we must do is define variables:
x = number of quarters
y = number of dimes
We now write the system of equations:
x + y = 28
0.25x + 0.10y = 4.05
Solving the system of equations we have:
x = 8.33
y = 19.66
Rounding:
x = 8
y = 20
Answer:
the college student has:
8 quarters
20 dimes
B E D M A S MEANS BRACKETS EXPONENTS DIVISION MULTIPLICATION ADDITION AND SUBTRACTION
Step-by-step explanation:
Simplify 1/125
1/125 . (x3))-1) ÷ 3
(x3
(———)-1) ÷ 3
125
3.1 x3 raised to the minus 1 st power = x( 3 * -1 ) = x-3
3.2 125 = 53 (125)-1 = (53)(-1) = (5)(-3)
x(-3)
——————— ÷ 3
(5)(-3)
x(-3)
Divide ——————— by 3
(5)(-3)
Answer: 125
/3x3
Break the two denominators down to their primes.
9: 3 * 3
12:2 * 2 * 3
LCD: 2*2*3*3
LCD: 4 * 9
LCD:36