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2 years ago

Doing a test please help

Mathematics

2 answers:

krok68 [10]2 years ago

8 0

Answer: its C

Step-by-step explanation do you want explanation?

Ainat [17]2 years ago

3 0

Answer:

The answer is C

Step-by-step explanation:

Hope this helps.

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Part F What is the mean absolute deviation for Doctor A’s data set on glasses? What is the mean absolute deviation for Doctor B’

frez [133]

There is more variability on glasses of doctor B's dataset than the glasses of doctor A's dataset

<h3>The doctors' mean absolute deviation on glasses</h3>

The dataset of doctor A is given as:

643 634 670 658 636 624 641 655 649 629

The dataset of doctor B is given as:

651 625 622 624 631 621 653 647 646 646

Using a statistical calculator, we have:

<u>Doctor A</u>

Doctor A: Mean Absolute Deviation (MAD) = 11.28
Doctor B: Mean Absolute Deviation (MAD) = 12

Hence, the mean absolute deviation is 11.28 for Doctor A’s and 12 for Doctor B’s data set on glasses

<h3>The variation of the two data</h3>

In a dataset, the larger the mean absolute deviations value, the larger the variation.

By comparison, 12 is greater than 11.28

Hence, there is more variability on glasses of doctor B's dataset than the glasses of doctor A's dataset

Read more about mean absolute deviation at:

brainly.com/question/3250070

#SPJ1

7 0

1 year ago

A rectangular prism has a length of 412 mm, a width of 412 mm, and a height of 6 mm. Sally has a storage container for the prism

astraxan [27]

LxWxH = 1018464
the other shape's volume is = 143 mm^3 this equals 2924207
to find the difference you would take them away from each other
1905743
hope this helped

HeyItsEihab

6 0

3 years ago

In the isosceles triangle ABC, we have AB=AC=4. The altitude from B meets AC at H. If AH=3(HC) then determine BC.

Inga [223]

Answer:

BC=√7

Step-by-step explanation:

AC=4

AC=AH+HC

=3HC+HC

=4HC

HC=1/4AC=1/4×4=1

AH=3HC=3×1=3

BH⊥ AC

AB=AC=4

$BC=\sqrt{AB^2-AH^2} =\sqrt{4^2-3^2} =\sqrt{16-9} =\sqrt{7}$

5 0

2 years ago

An object is acted upon by the forces F1=<10,6,4> and F2=<0,3,9>. Find the force F3 that must act on the object

murzikaleks [220]

$\vec F_3=\langle x,y,z\rangle$ is a force vector such that

$\vec F_1+\vec F_2+\vec F_3=\vec0$

$\implies\langle10,6,4\rangle+\langle0,3,9\rangle+\langle x,y,z\rangle=\langle0,0,0\rangle$

$\implies\begin{cases}10+x=0\\9+y=0\\13+z=0\end{cases}\implies x=-10,y=-9,z=-13$

So the missing force is

$\boxed{\vec F_3=\langle-10,-9,-13\rangle}$

8 0

2 years ago

Find two numbers if there sum is 7.2 and their difference is 2.7

Sidana [21]

Answer:

2.25 and 4.95

Step-by-step explanation:

x + y = 7.2

x - y = 2.7

x = 7.2 - y

x - y = 2.7

(7.2 - y) - y = 2.7

7.2 - 2y = 2.7

-2y = 2.7 - 7.2

-2y = -4.5

-2y/-2 = -4.5/-2

y = 2.25

x + y = 7.2

x + 2.25 = 7.2

x = 7.2 - 2.25

x = 4.95

Check: 4.95 and 2.25

x + y = 7.2

(4.95) + (2.25) = 7.2

7.2 = 7.2

x - y = 2.7

(4.95) - (2.25) = 2.7

2.7 = 2.7

6 0

3 years ago

Read 2 more answers