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Ipatiy [6.2K]
3 years ago
5

Simplify : a)

"\sqrt{x} 0.49x^1^8" align="absmiddle" class="latex-formula"> when x<0
Simplify : b) 15\sqrt{x} 0.16c^1^2 x can be anything
Mathematics
1 answer:
Sidana [21]3 years ago
4 0
<h2>The value of \sqrt{x}0.49x^{18} = 0.49x^{\dfrac{37}{2}}</h2>

Step-by-step explanation:

We have,

 \sqrt{x(0.49)}x^{18}

To find, the value of \sqrt{x(0.49)}x^{18} = ?

∴  \sqrt{x(0.49)}x^{18}

= 0.7x^{\dfrac{1}{2}} x^{18}

= 0.7x^{18+\dfrac{1}{2}}

Using the identity,

a^{m}.a^{n}=a^{m+n}

= 0.7x^{\dfrac{36+1}{2}}

= 0.7x^{\dfrac{37}{2}}

Thus, the value of \sqrt{x(0.49)}x^{18} = 0.49x^{\dfrac{37}{2}}

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