Question

Simplify : a) "\sqrt{x} 0.49x^1^8" align="absmiddle" class="latex-formula"> when x<0
Simplify : b) $15\sqrt{x} 0.16c^1^2$ x can be anything

Answer 1

The value of $\sqrt{x}0.49x^{18}$ = $0.49x^{\dfrac{37}{2}}$

Step-by-step explanation:

We have,

 $\sqrt{x(0.49)}x^{18}$

To find, the value of $\sqrt{x(0.49)}x^{18}$ = ?

∴  $\sqrt{x(0.49)}x^{18}$

= $0.7x^{\dfrac{1}{2}} x^{18}$

= $0.7x^{18+\dfrac{1}{2}}$

Using the identity,

$a^{m}.a^{n}=a^{m+n}$

= $0.7x^{\dfrac{36+1}{2}}$

= $0.7x^{\dfrac{37}{2}}$

Thus, the value of $\sqrt{x(0.49)}x^{18}$ = $0.49x^{\dfrac{37}{2}}$