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Annette [7]
3 years ago
13

What is the measure of the angle formed by the minute hand and the hour hand of a clock when the clock shows 4:00?

Mathematics
2 answers:
Misha Larkins [42]3 years ago
5 0

Answer:

120^o

Step-by-step explanation:

We are asked to find the measure of the angle formed by the minute hand and the hour hand of a clock when the clock shows 4:00.

Since we know that clock is a circle made of 360 degrees.

Angle described by minute hand in one minute equals to 6 degrees (360/60). Angle described by hour hand in 1 hour equals 30 degrees (360/12).

At 4:00 minute hand will be at 12 and hour hand will be at 4. So we will multiply 4 by 30 to find the measure of angle formed when the clock shows 4:00.

\text{Measure of angle}=4\times 30^o

\text{Measure of angle}=120^o

Therefore, the measure of the angle formed by the minute hand and the hour hand of a clock, when the clock shows 4:00 is 120 degrees.

hram777 [196]3 years ago
4 0
The answer to this is 120. 
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3 years ago
Rectangle has a length that is 5 inches greater than its width, and its area is 104 square inches. The equation (x + 5)x = 104 r
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X2 + 5x – 104 = 0
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3 years ago
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Part 2: Identify the vertex, focus, and directrix of each. Then sketch the graph.
Andre45 [30]

Answer:  \bold{1.\quad \text{Vertex}}:(-3,-6)\qquad \text{Focus}:\bigg(-3,-\dfrac{17}{4}\bigg)\qquad \text{Directrix}:y=-\dfrac{19}{4}

               2.  Vertex: (-5, 4)           Focus: (-6, 4)                 Directrix: x = -4

<u>Step-by-step explanation:</u>

The vertex form of a parabola is y = a(x - h)² + k  or  x = a(y - k)² + h

  • (h, k) is the vertex
  • p is the distance from the vertex to the focus
  • -p is the distance from the vertex to the directrix

    \bullet \quad a=\dfrac{1}{4p}

1) y = (x + 3)² - 6        →       a = 1      (h, k) = (-3, -6)

a=\dfrac{1}{4p}\qquad \rightarrow \qquad 1=\dfrac{1}{4p} \qquad \rightarrow \qquad p=\dfrac{1}{4}\\\\\text{Focus = Vertex + p}\\\\.\qquad =\dfrac{-18}{4}+\dfrac{1}{4}\\\\.\qquad = -\dfrac{17}{4}\qquad \rightarrow \qquad \text{Focus}=\bigg(-3,-\dfrac{17}{4}\bigg)\\\\\\\text{Directrix: y = Vertex - p}\\\\.\qquad \quad y=\dfrac{-18}{4}-\dfrac{1}{4}\\\\.\qquad \quad y= -\dfrac{19}{4}

****************************************************************************************

2.\quad x=-\dfrac{1}{4}(y-4)^2-5\qquad \rightarrow \quad a=\dfrac{1}{4}\qquad (h, k)=(-5,4)

a=\dfrac{1}{4p}\qquad \rightarrow \qquad -\dfrac{1}{4}=\dfrac{1}{4p} \qquad \rightarrow \qquad p=-1\\\\\text{Focus = Vertex + p}\\\\.\qquad =-5+\ -1\\\\.\qquad = -6\qquad \rightarrow \qquad \text{Focus}=(-6,4)\\\\\\\text{Directrix: y = Vertex - p}\\\\.\qquad \quad y=-5+\ -1\\\\.\qquad \quad y= -4

7 0
4 years ago
What is the equation<br>​
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We substitute the values to obtain;

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8 0
3 years ago
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4 0
3 years ago
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