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Natasha2012 [34]
2 years ago
11

Captain American throws his shield straight down off a roof with a speed of 50 m/s . What is the acceleration of the shield half

way down to the ground?
Physics
1 answer:
Nutka1998 [239]2 years ago
6 0

<em>IF</em> this is happening on <u>Earth</u>, then the acceleration of gravity wherever the captain and the roof are is about 9.8 m/s² downward.

<em>IF</em> his shield is not affected by air resistance, and it's free to behave under the influence of gravity alone, then its acceleration is <em>9.8 m/s² downward</em>, from the moment it leaves his hand until the moment it hits a building, a tree, a car, a bus, an evildoer, or the ground.  

Whatever speed it has when it leaves his hand, in whatever direction, makes no difference.

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Which of the following is true?
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Answer:

D

Explanation:

What it means to be an autotroph is that you make your own food and plants do that by photosynthesis to be a heterotroph is finding food from other sources like autotrophs or even other heterotrophs

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14. Which of the following is an example of
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Answer:

none of the above or screwdriver

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A car is being driven down a level track with no net force on it. This motion is best described as
Alex

A)Linear motion

If there is not net force on the car, then by the Newton Second Law, the acceleration is zero, and the only valid option for zero acceleration is A).

3 0
2 years ago
A bus and a car have an inelastic head-on collision. The bus has a mass of 1.5 × 103 kilograms and an initial velocity of 20 met
makkiz [27]

Answer:

+5300 kg m/s

Explanation:

In any type of collision, the total momentum is conserved. Therefore, we can just calculate the total momentum before the collision, and the final momentum will be equal to the initial one.

The total momentum before the collision is:

p_i = m_1 u_1 + m_2 u_2

where

m_1 = 1.5 \cdot 10^3 kg is the mass of the bus

m_2 = 9.5\cdot 10^2 kg is the mass of the car

u_1 = 20 m/s is the initial velocity of the bus

u_2 = -26 m/s is the initial velocity of the car

Substituting the numbers, we find

p_1 = (1.5 \cdot 10^3 kg)(20 m/s)+(9.5\cdot 10^2 kg)(-26 m/s)=5300 kg m/s

And since the total momentum is conserved, this is also the final momentum after the collision.

7 0
3 years ago
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An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 28.9
Lera25 [3.4K]

Answer:

a = 0.016 m/s^2

the airplane's acceleration is 0.016 m/s^2

Explanation:

Applying the equation of motion;

v^2 = u^2 + 2as ........1

Where;

v = final velocity = 47.5 m/s

u = initial velocity = 28.9 m/s

a = acceleration

s = displacement = 45300m

From equation 1, making a the subject of formula;

v^2 = u^2 + 2as

2as = v^2 - u^2

a = (v^2 - u^2)/2s

Substituting the given values;

a = (47.5^2 - 28.9^2)/(2×45300)

a = 0.015684768211 m/s^2

a = 0.016 m/s^2

the airplane's acceleration is 0.016 m/s^2

5 0
2 years ago
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