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AleksandrR [38]
3 years ago
7

A stationary hockey puck has a mass of 0.27 kg. A hockey player uses her stick to apply a 18 N force over a distance of 0.42 m.

How much work does this force do on the puck?
Group of answer choices

7.6 J

-43 J

-7.6 J

28 J

43 J
Physics
1 answer:
jeka57 [31]3 years ago
3 0
W=Fs
W=18(0.42)
W=7.56

Answer: 7.6 J (first option)
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A mass m1=1.5 kg rests on a 30 degree ramp with a coefficient of kinetic friction = 0.40. Mass m1 is tied to another mass m with
soldier1979 [14.2K]

Answer:

m = 2.31 Kg

Explanation:

given,

m₁ is the mass rest on the inclined plane = 1.5 Kg

inclination of plane = 30°

Kinetic friction = μ = 0.4

acceleration of the body = 2.68 m/s²

mass m is hanging  = ?

using equation to solve

T - m₁g sin θ - μ m₁g cos θ = m₁ a

on the block on inclined plane there will be acting tension T on the string,

mg sin θ will be the force acting opposite to the tension on the string and a frictional force will be acting which will oppose moment which will be equal to  μ m₁g cos θ

T = m₁(g sin θ +  μ g cos θ + a )

T = 1.5 (9.8 x sin 30° +  0.4 x 9.8 x cos 30°+ 2.68 )

T = 16.46 N

now, forces on the other side of pulley

m g - T = m a

m (g - a ) = T

m = \dfrac{16.46}{9.8-2.68}

m = 2.31 Kg

6 0
3 years ago
the triceps muscle in the back of the upper arm extends the forearm. this muscle in a professional boxer exerts a force of 2.00×
Alexus [3.1K]

Answer: 0.512 kgm²

Explanation:

Given

Force, F = 2*10^3 N

Angular acceleration, α = 121 rad/s²

Lever arm, r(⊥) = 3.1 cm = 3.1*10^-2 m

τ = r(⊥) * F

Also,

τ = Iα

Using the first equation, we have

τ = r(⊥) * F

τ = 0.031 * 2*10^3

τ = 62 Nm

Now we calculate for the inertia using the second equation

τ = Iα, making I subject of formula, we have

I = τ / α, on substituting, we have

I = 62 / 121

I = 0.512 kgm²

Thus, the moment of inertia of the boxers forearm is 0.512 kgm²

5 0
4 years ago
A wheel of diameter 78 cm has an axle of diameter 14.8 cm. A force 150 N is exerted along the rim of the wheel.What force should
bezimeni [28]

Answer:

F = 263.51 N

Explanation:

given,

diameter of wheel = 78 cm

diameter of axle = 14.8 cm

Force exerted on the rim of wheel = 150 N

Force applied outside the axle = ?

To prevent rotation wheel from rotating the Force 'F' should be applied outside of the axle.

Net momentum about the center of mass should be zero

now,

Moment of about center due to 150 N = moment about center due to F on axle

50\times \dfrac{78}{2}=F\times \dfrac{14.8}{2}

           7.4 F = 1950

                F = 263.51 N

Hence, Force exerted outside of the axle in order to prevent the wheel from rotating is equal to 263.51 N.

6 0
4 years ago
How does the gravitational force between two objects change if the distance between the objects doubles?
Ymorist [56]

if the distance between the objects is doubled the force is reduced by a factor of 4

<h3>Whats is gravitational force?</h3>

Gravitational force is the force of attraction between objects in the universe.

f = G * m1 * m2 / r^2

f = gravitational force

G = gravitational constant

m1 = mass of object 1

m2 = mass of object 2

r = distance between the objects

From the formular, the gravitational force and the distance is an inverse relationship so increasing the distance by a factor results to reduction of the force by the square of the factor. hence doubling the distance which is distance mutiplied by 2 will lead to reduction of the force by 2^2 = 4

Therefore: The force decreases by a factor of 4.

hope it helps

4 0
2 years ago
True<br> False<br><br> PLEASE HELP
harkovskaia [24]

Answer:

False

Explanation:

10 is not the same as -10 but if -10 is the absolute value they would be the  same

Give me brainllest

6 0
3 years ago
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