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STatiana [176]
3 years ago
15

Identify the function that best models the given data.

Mathematics
1 answer:
jonny [76]3 years ago
5 0
The function that best models the given data is:

B) 3.125x^2 - 14.5x + 208.5 

To prove this you plug 6 (which is the number of trees) instead of x

3.125x^2 - 14.5x + 208.5 
3.125(6)^2 - 14.5(6) + 208.5 
112.5 - 87 + 208.5 
=234
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Simplify (-6)×(-6)^2​
alexdok [17]

Answer:

-216

(-6)^3

Step-by-step explanation:

-6 * (-6*-6)

-6 * 36

-216

or

-6 * -6 *-6

This is -6 multiplied together 3 times

(-6) ^3

8 0
3 years ago
Joni has a box that a mass of 67 dekagrams she converts this to centigrams her work is shown below
7nadin3 [17]
<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Joni should have multiplied by 1000 because 1 dekagram is equal to 1000 centigrams.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

4 0
4 years ago
Read 2 more answers
Please use ( y = mx +b )
Sindrei [870]

Answer:

y= 2/5-1

Step-by-step explanation:

You get the 2/5 because you go 2 to the right and go 5 up, the -1 is because the x-int is at -1.

6 0
3 years ago
19. The marked price of an oven is 30% above its cost. In a sale, it is
yaroslaw [1]

a) Marked price: $884, Cost: $680

b) 2.5 %

Step-by-step explanation:

a)

Let's call:

P = marked price of the oven

C = cost of the oven

We know that:

- The marked price of the oven is 30% above the cost, which means

P=(1+\frac{30}{100})C=1.30C (1)

- In the sale, the oven is sold at a discount of 25% on its marked price; so the price of the sale is (we call it S)

S=(1-\frac{25}{100})P=0.75P (2)

- We also know that the discount, which is the difference between the makerd price (P) and the discounted price (S) is

P-S=\$221 (3)

Substituting (2) into (3) we find marked price

P-0.75P=\$221\\0.25P=\$221\\P=\frac{221}{0.25}=\$884

Therefore, the cost of the oven is (from eq(1)):

C=\frac{P}{1.30}=\frac{884}{1.30}=\$680

b)

The percentage loss in this situation is given by the difference between cost of the oven and the final price at which the oven is sold.

In this case, we have:

C = $680 (cost of the oven)

The discounted prices is S, and can be f ound using eq(3):

S=P-221=884-221=\$663

Therefore, the oven costs 680$ but it is sold at 663$.

Therefore, we can calculate the percentage loss using the equation:

Loss=\frac{C-S}{C}\cdot 100 = \frac{680-663}{680}\cdot 100 =0.025\cdot 100 = 2.5\%

So, a percentage loss of 2.5%.

4 0
3 years ago
Help me please, asap-
Nimfa-mama [501]
The answer is 191/30

8 0
2 years ago
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