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3 years ago

14

The volume of a cylinder with base radius 3 cm in height 6 cm is what cubic centimeters

1 answer:

Sindrei [870]3 years ago

5 0

Answer:

22/7 * 3 * 3 * 6 ~ 169.65 cubic centimeters

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9 is a factor of which number? <br> 12<br> 18<br> 23<br> 28

Angelina_Jolie [31]

Answer:

The answer is 18.

Step-by-step explanation:

9x2=18

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3 years ago

When I graphed the linear function, it turned out to be a wavy curve.

Elden [556K]

Answer:

B. The statement does not make sense because a linear function has a straight-line graph.

Step-by-step explanation:

Linear functions have a general form y = m*x +b and only yield straight-line graphs. Therefore, the statement does not make sense, either the graphed function is not linear, or there was an error in the graphing process. The answer is alternative B.

*Note that alternative D is wrong because it is incomplete, since linear functions can have a rate of change that increases (m > 0), decreases (m < 0) or that is zero (m = 0).

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3 years ago

Write −12.405 as a mixed number in simplest form

serious [3.7K]

Answer:

$-12\frac{81}{200}$

Step-by-step explanation:

In the decimal of −12,405, leave the −12 and divide 405 by 1000 for now:

$\frac{81}{200} = \frac{405}{1000}$

Greatest Common Divisor [GCD]: 5

Finally, you attach this back to the −12, giving you $-12\frac{81}{200}$ .

I am joyous to assist you anytime.

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3 years ago

8x-11<3 solve the inequality please i need help now

Mamont248 [21]

Answer: if u where doing 8x-11 that would = -88

Step-by-step explanation:

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3 years ago

Suppose the average tread-life of a certain brand of tire is 42,000 miles and that this mileage follows the exponential probabil

Ahat [919]

Answer: The probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

Step-by-step explanation:

The cumulative distribution function for exponential distribution is :-

$P(X\leq x)=1-e^{\frac{-x}{\lambda}}$ , where $\lambda$ is the mean of the distribution.

As per given , we have

Average tread-life of a certain brand of tire : $\lambda=\text{42,000 miles }$

Now , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles will be :

$P(X\leq 65000)=1-e^{\frac{-65000}{42000}}\\\\=1-e^{-1.54761}\\\\=1-0.212755853158\\\\=0.787244146842\approx0.7872$

Hence , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

8 0

3 years ago