The cost for each serving of soup is $0.62
<u>Step-by-step explanation:</u>
Diameter =3.5 inches
Radius = 1.75 inches
Height = 5 inches
Each serving of soup = 15 cubic inches
Cost of the can = $1.99
Volume of the can = π(1.75 x 1.75) 5
= (3.14) (3.0625) 5
= 48.08 cubic inches
For 48 cubic inches of soup the cost is $1.99
For 15 cubic inches of soup the coat will be,
Cost = (15x1.99) /48
= $0.62
The cost for each serving of soup is $0.62
(2x-5y)+(x+y)=(2x+x)+(-5y+y)=3x-4y.
therefore:
(2x-5y)+(x+y)=3x-4y
486/6=81
Square root 81 = one side length = 9m
volume = 9^3 = 729
Answer:
Dh/dt = 0.082 ft/min
Step-by-step explanation:
As a perpendicular cross section of the trough is in the shape of an isosceles triangle the trough has a circular cone shape wit base of 1 feet and height h = 2 feet.
The volume of a circular cone is:
V(c) = 1/3 * π*r²*h
Then differentiating on both sides of the equation we get:
DV(c)/dt = 1/3* π*r² * Dh/dt (1)
We know that DV(c) / dt is 1 ft³ / 5 min or 1/5 ft³/min
and we are were asked how fast is the water rising when the water is 1/2 foot deep. We need to know what is the value of r at that moment
By proportion we know
r/h ( at the top of the cone 0,5/ 2) is equal to r/0.5 when water is 1/2 foot deep
Then r/h = 0,5/2 = r/0.5
r = (0,5)*( 0.5) / 2 ⇒ r = 0,125 ft
Then in equation (1) we got
(1/5) / 1/3* π*r² = Dh/dt
Dh/dt = 1/ 5*0.01635
Dh/dt = 0.082 ft/min
