When I graphed the linear function, it turned out to be a wavy curve.

Mathematics

1 answer:

Elden [556K]3 years ago

4 0

Answer:

B. The statement does not make sense because a linear function has a straight-line graph.

Step-by-step explanation:

Linear functions have a general form y = m*x +b and only yield straight-line graphs. Therefore, the statement does not make sense, either the graphed function is not linear, or there was an error in the graphing process. The answer is alternative B.

*Note that alternative D is wrong because it is incomplete, since linear functions can have a rate of change that increases (m > 0), decreases (m < 0) or that is zero (m = 0).

You might be interested in

Find the area of a regular nonagon with a side length of 9 and an apothem of 16

Sever21 [200]

Idk if i'm exactly right but i think it's 500.73

6 0

3 years ago

Classify the following triangle check all that apply

Oksanka [162]

You did not attach an image

6 0

4 years ago

emily earns $75 per day plus a commission. her commission is 15%. she sells $600 worth of furniture. how much does she earn for

iragen [17]

It would be $165. If she earns $75 a day, plus what she make from selling the furniture. That 15% of $600 is $90. Simply add $90+$75 and your answer is $165.

5 0

3 years ago

If a = (3-2√2) find the value of a4+ 1/a4

FinnZ [79.3K]

Answer:

1154

Step-by-step explanation:

Perhaps the easiest way to evaluate this numerical expression is to let a calculator do it. Alternatively, we can compute the value from a +1/a.

<h3>expression</h3>

Consider the square of a +1/a:

(a +1/a)^2 = a^2 +2(a)(1/a) +1/a^2 = (a^2 +1/a^2) +2

This means ...

a^2 +1/a^2 = (a +1/a)^2 -2

Similarly, using a^2 for 'a' in the above, we have ...

a^4 +1/a^4 = (a^2 +1/a^2)^2 -2

<h3>numerical value</h3>

The value of a +1/a is ...

$a+\dfrac{1}{a}=3-2\sqrt{2}+\dfrac{1}{3-2\sqrt{2}}=(3-2\sqrt{2})+\dfrac{3+2\sqrt{2}}{3^2-(2\sqrt{2})^2}\\\\=(3-2\sqrt{2})+(3+2\sqrt{2})\\\\a+\dfrac{1}{a}=6$