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Verizon [17]
3 years ago
8

The perimeter of a rectangular sandbox is 28ft. The length is six times the width.

Mathematics
1 answer:
VLD [36.1K]3 years ago
7 0
Let the width =x
length = 6x
p=14x
28=14x
x=2
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The number of customers in a store on the first day is represented by: (6x - 3) The number of customers on the second day is rep
Scorpion4ik [409]

Answer:the expression is 5x - 2

Step-by-step explanation:

The number of customers in a store on the first day is represented by: (6x - 3).

The number of customers on the second day is represented by: (x - 1)

An expression to find how many more customers visited the store on the first day would be the difference between the number of customers that visited the store on the first day and the number of customers that visited the store on the second day. The expression becomes

6x - 3 - (x - 1)

= 6x - 3 - x + 1

= 6x - x - 3 + 1

= 5x - 2

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3 years ago
Which angles are corresponding angles?
FromTheMoon [43]

Answer:

D, E, F, C,

Step-by-step explanation:


8 0
3 years ago
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Y = 5x - 22 y = 4x - 17
Pie
The answer is (5,3). You need to equal both sides out. So 5x-22=4x-17. That will give you x=5. After that you substitute 5 for x in one or both of the equations and get that y=3. Hope this helps!
6 0
3 years ago
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Jose reads his book at an average rate of 2.5 pages every four minutes. If Jose continues to read at exactly the same rate what
madreJ [45]

it would take him 32 minutes. You could use divisoin and multiplecation to figure it out

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3 years ago
Solve the system of equations: <br> X+y+z=5<br> -3x-4y+4z=15<br> 2x-y-4z=-8
atroni [7]

Answer:

  (x, y, z) = (3, -2, 4)

Step-by-step explanation:

The attachment shows a solution using a graphing calculator where the first equation is solved for z, and that expression is substituted into each of the other two equations. The solution to that system is (x, y) = (3, -2). Using these values in the expression for z, we find ...

  z = 5 -(3 +(-2)) = 4

The solution is (x, y, z) = (3, -2, 4).

__

Your graphing calculator and/or online tools can give you the reduced row echelon form of the augmented matrix representing the system:

  \left[\begin{array}{ccc|c}1&1&1&5\\-3&-4&4&15\\2&-1&-4&-8\end{array}\right]

__

If you're solving by hand, you can do the substitution described above to eliminate z from one equation. You can eliminate z from another equation by adding the last two:

  -3x -4y +4(5 -x -y) = 15   ⇒   -7x -8y = -5

  (-3x -4y +4z) +(2x -y -4z) = (15) +(-8)   ⇒   -x -5y = 7

This pair of equations can be solved for x and y in any of the usual ways. Using the second equation to substitute for x, for example, gives you ...

  -7(-5y -7) -8y = -5   ⇒   27y = -54   ⇒   y = -2

  x = -5(-2) -7 = 3

  z = 5 -(3) -(-2) = 4

_____

<em>Additional comment</em>

If all that is needed is a solution, we prefer a graphical or matrix approach. These take about the same amount of time. Both require a little additional effort to determine exact values when the solutions are not integers.

6 0
2 years ago
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