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Nataly [62]
3 years ago
8

A line has a y-intercept of 7 and a slope of 2 . what is it’s equation in slope-intercept form

Mathematics
2 answers:
BARSIC [14]3 years ago
8 0

Answer:

y=2x+7

Step-by-step explanation:

the slope is always the number before x. the y-intercept is the number added after x

11111nata11111 [884]3 years ago
7 0

Answer:

y=2x+7

Step-by-step explanation:

y=mx+b is the formula

y=2x+7 should be the equation. Sorry if i'm wrong, let me know!

But hope this helps!

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Can someone help me with this problem.
Ipatiy [6.2K]

Answer:

16,912 is the answer, Because you have to add it all up, then divide by 2, and then find the closest to your answer.

Step-by-step explanation:

7 0
2 years ago
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6+2(7×-3) Simplify the expression
almond37 [142]

Answer:

=36

Step-by-step explanation:

6+2(7*(-3) )\\\\=6+2(-21)\\\\=6-42\\\\=2+4-42\\\\=4-40\\\\=36

7 0
3 years ago
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Complete the recursive formula of the geometric sequence -0.56\,,-5.6\,,-56\,,-560,...−0.56,−5.6,−56,−560,...Minus, 0, point, 56
pentagon [3]

Answer:

The recursive formula is:

Cn = 10C(n-1)

Step-by-step explanation:

Given the geometric sequence.

-0.56, -5.6, -56, -560, ...

The common ratio is

-5.6/-0.56 = -56/-5.6 = -560/-56 = ... = 10

The recursive formula is easily

Cn = C(n-1) × 10

That is a number is ten times the preceding number.

7 0
3 years ago
Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers​
lidiya [134]

Answer:

6-3\sqrt{3}

If you compare this to a+b\sqrt{3}, then a=6 and b=-3.

Step-by-step explanation:

We are given x=\sqrt{3}-1 and we are asked to find the value of x^2-x+1.

So we will need to find x^2.

x=\sqrt{3}-1

Square both sides:

x^2=(\sqrt{3}-1)^2

Expand using identity: (x-a)^2=x^2-2ax+a^2.

x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2

x^2=3-2\sqrt{3}+1

x^2=4-2\sqrt{3}

Let's go back to the full x^2-x+1.

x^2-x+1

(4-2\sqrt{3})-(\sqrt{3}-1)+1

4-2\sqrt{3}-\sqrt{3}+1+1

6-3\sqrt{3}

If you compare this to a+b\sqrt{3}, then a=6 and b=-3.

5 0
3 years ago
To which graph does the point (−1, 3) belong? y ≥ 2x + 6 y ≥ 3x − 1 y ≥ −x + 3 y ≥ −2x + 5
Anna35 [415]
Well first find the slope of the point
y=mx+b  y=-1x+3
slope = -1
then put the problem in point slope form y - y1 = m (x-x1)
y + 3 = -1 (x+1) then solve for y=mx+b again
so y> 2x + 6 is the answer
4 0
3 years ago
Read 2 more answers
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