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3 years ago

1) During a football game, a team lost 10 yards and then gained 9 yards. What is the net gain or loss for the team?

Mathematics

1 answer:

Setler79 [48]3 years ago

5 0

1) the answer is net loss of 1
2) a gain of 2 Bc -10 + 12= 2

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B = 23a + 1<br> b = -13a + 7

ohaa [14]

The answer is the question

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3 years ago

Please help!!!! trigonometric ratios !!!

OLga [1]

Answer:

X=47.68degree

Step-by-step explanation:

tanx=56/51

x=tan^(-1)(56/51)

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3 years ago

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The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the

Darya [45]

Answer:

Brand 1 Brand 2 Difference

37734 35202 2532

45299 41635 3664

36240 35500 740

32100 31950 150

37210 38015 −805

48360 47800 560

38200 37810 390

33500 33215 285

Sum of difference = 2532+ 3664+740+150 −805+ 560 +390 +285 = 7516

Mean = $d=\frac{7516}{8}$

Mean = $d=939.5$

a) d= 939.5

$\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}$

$=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}$

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, $t_{\frac{\alpha}{2}}=3.499$

Formula for confidence interval $= \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)$

Substitute the values

confidence interval $= 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

confidence interval $= 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$ to $= 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

Confidence interval $−843.396\$ to $2722.396$

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3 years ago

What is the slope of (1, -3/4) and (4, -3)

Alex777 [14]

Answer:

1-5

Step-by-step explanation:

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3 years ago

The line that divides a parabola in half is..?

mojhsa [17]

The line of symmetry.

It divides the parabola into to halves that are exactly the same.

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