In order to do this you list them from least to greatest. 14, 24, 29, etc.
Answer:
B
Step-by-step explanation:
![6^{\frac{1}{4} } b^{\frac{3}{4} }c^{\frac{1}{4} }\\\\=(6^1b^3c^1)^{\frac{1}{4} }\\\\=(6b^3c)^\frac{1}{4} \\\\=\sqrt[4]{6b^3c}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20b%5E%7B%5Cfrac%7B3%7D%7B4%7D%20%7Dc%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%5C%5C%5C%5C%3D%286%5E1b%5E3c%5E1%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%5C%5C%5C%5C%3D%286b%5E3c%29%5E%5Cfrac%7B1%7D%7B4%7D%20%5C%5C%5C%5C%3D%5Csqrt%5B4%5D%7B6b%5E3c%7D)
so answer is B
Answer
17 m^3
Explanation
Volume of a given prism = bh
Where b = base area and h = height of prism
Base area = 1 • 2/2 (b • h /2)
= 1
Height = 17
17 • 1 = 17 m^3
Answer:
Step-by-step explanation:
I'm not sure I know what the paper ball situation is, but I can tell you that especially when working with a set formula in physics, math or chemistry (I'd include biology if I knew any biology) that it is a good idea to write down your givens.
The equation you are given is going to fall apart once you know what your givens are and what they do.
I just looked up the Paper Ball Situation. This is a wonderful piece of physics. It immediately opened up all sorts of treasures once they experimenters thought of using tin foil. Givens are a necessity in such an experiment.
Explanation: The y axis is the line that goes up and down, vertical. The x axis is the line that goes straight across, horizontal. So, when looking for intercepts we have to see what numbers your graphed line goes through.
Make sure when you are writing your points you write it in (x,y) form. If you don't it will be wrong.
So, for our x intercept it would be -7,0.
This is because your graphed line goes through x at -7 and it has no y, so that would be 0.
For your y intercept, it would be 0,2
This is because our line does not go through x, so we make that 0. It does go through y at 2.
Hope this helps :)
If you need elaboration on anything let me know. I know sometimes with math it is kind of hard to explain through typing.
