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Monica [59]
3 years ago
5

The Hardy–Weinberg equilibrium model states that allele and genotype frequencies in a population will remain constant from gener

ation to generation in the absence of other evolutionary influences. Because one or more of the influences listed above are typically present in real populations, the Hardy–Weinberg model describes an ideal condition against which the effects of these influences can be analyzed. Of the influences listed, which would not cause a change in allelic frequencies or genotype?
a) Mutation
b) Genetic Drift
c) Mitotic Divison
d) Sexual Selection
Biology
2 answers:
olga_2 [115]3 years ago
6 0
THE ANSWER IS C.) MITOTIC DIVISON



I GOT IT RIGHT ON USATESTPREP...
malfutka [58]3 years ago
3 0
The answer is c. Hope u get it right
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The process of water blowing across the cell membrane from areas of higher concentration to areas of lower concentration what is the flow of water called Diffusion.

6 0
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Why does compact bone have canaliculi, but spongy bone does not?
stich3 [128]
Canaliculi are tiny canals in bone between osteocytes containing osteocyte cell processes. A spongy bone, also known as a cancellous bone, is a bone with latticelike appearance. A compact bone is a bone that is denser and has fewer spaces than cancellous bone. A compact bone has canaliculi but the spongy bone doesn't, because compact bone tissues form the outer layer of the bone while the cancellous bone tissues form the inner layer of the bone and it does not have osteons. Anosteon is a single central canal, with its contents, and the associated lamellae and osteocytes surrounding it. 
4 0
3 years ago
In most sexually reproducing organisms, the diploid phase of the life cycle begins at
valkas [14]

The diploid phase of the life cycle begins with the formation of the zygote.

Meiosis is referred to the type of cell division which occurs in the production

of male and female sex cells. This also occurs during sexual reproduction.

Parent cells provide male and sex cells such as sperm and egg which

contains DNA. They then fuse together to form a zygote which is the diploid

phase as a result of the fusion of two haploid cells. The zygote then

continues to undergo some meiotic processes which reduces it to back to a

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Read more on brainly.com/question/16249478

4 0
3 years ago
Monosaccharides are building blocks of larger carbohydrates.<br><br> True<br> False
ale4655 [162]
The answer to this is true. 
7 0
3 years ago
Indicate the expected number of Barr bodies in interphase cells of individuals with Klinefelter syndrome; Turner syndrome; and k
madreJ [45]

Answer:

Barr bodies are small bodies that are dark staining bodies that show the inactivated X chromosome, these sex chromatin bodies attach to the membrane of the nucleus of interphase cells.

One less of the total number of X-chromosome (n-1) represents the number of Barr bodies.

Then,

The number of Barr bodies with Klinefelter would be:

Klinefelter (47,XXY): (n-1) = (2-1) = 1 Barr body as here two X chromosome present.

Similarly, for

Turner (45,XO): (n-1) = (1-1) = 0 Barr bodies (X chromosome = 1)

Now, as per the question, the bar bodies for karyotypes given

47,XYY: (n-1) = (1-1) = 0 Barr bodies

47,XXX: (n-1) = (3-1) = 2 Barr bodies

48,XXXX: (n-1) = (4-1) = 3 Barr bodies

7 0
3 years ago
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