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harkovskaia [24]
3 years ago
11

What is the area of the shaded sector? Leave your answer in terms of Pi.

Mathematics
1 answer:
pav-90 [236]3 years ago
4 0
Number 3 because it holds the smallest decimal!
You might be interested in
HELP PLEASE
oee [108]
Using a graph tool

case 1) 
2x-y=-13
y=x+9

the solution is the point (-4,5)
see the attached figure N 1

case 2)
y=3x-7
y=2x-5

the solution is the point (2,-1)
see the attached figure N 2

case 3)
3x+2y=10
6x-y=10

the solution is the point (2,2)
see the attached figure N 3

case 4)
y=6
x=-5
the solution is the point (-5,6)
see the attached figure N 4

case 5)
4x-3y=5
3x+2y=-9
the solution is the point (-1,-3)


case 6)
x+y=7
x-y=-1
the solution is the point (3,4)

the answer in the attached figure



6 0
4 years ago
Plz help!!!!!!!!!!!!
sergejj [24]

Answer:

-8

Step-by-step explanation:

(-32)^(3/5) is equivalent to (-2^5)^(3/5) and applying exponent rules then simplifying you can get your answer.

4 0
3 years ago
Read 2 more answers
Rewrite the equation in polar form.
ycow [4]

Answer:

C) √5(cos(117°) +i·sin(117°))

Step-by-step explanation:

The rectangular number a+bi can be written in polar form as ...

√(a^2+b^2)×(cos(arctan(b/a)) + i·sin(arctan(b/a)))

Here, we have a=-1, b=2, so the magnitude is ...

√((-1)^2 +2^2) = √(1+4) = √5

and the angle is ...

arctan(2/(-1)) = arctan(-2) ≈ 116.565° . . . . . a 2nd-quadrant angle

Then you have ...

-1 +2i = √5(cos(117°) +i·sin(117°)) . . . . . . customary "polar form"

_____

Comment on the answer

The "polar form" is generally written as ...

(magnitude)·(cos(angle) +i·sin(angle))

You may also see it as ...

(magnitude) cis (angle) . . . . . . . where "cis" is shorthand for "cos + i·sin"

In my engineering courses, we often used the form ...

(magnitude) ∠ (angle)

The form used by my calculator is ...

(magnitude)·e^(i·angle) . . . . . where angle is usually in radians

4 0
3 years ago
Hailey paid $13 for 1 3/7 kg of sliced salami<br> whats the cost per kg of salami?
hodyreva [135]

Answer:

if she paid $13 for

1 \frac{3}{7}

she actually paid

\frac{7}{7}  +  \frac{3}{7}  =  \frac{10}{7}

so 13÷10=1.3$ per kg

hope it's right and hope I helped

8 0
3 years ago
: figure below, find the exact value of z.
ss7ja [257]
See photo for solution

7 0
3 years ago
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