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3 years ago

Which equation is true for x = 6? A) 2x + 5 = 25 B) 3x + 5 = 17 C) 5x − 18 = 7 D) 6x − 10 = 26

Mathematics

1 answer:

Anit [1.1K]3 years ago

4 0

D is the answer.
6×6-10=26

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Daniel is constructing a fence that consists of parallel sides line AB and line EF. Complete the proof to explain how he can sho

Anit [1.1K]

Answer:

its 1

Step-by-step explanation:

got it right o the test

3 0

3 years ago

Help me please ^^ much appreciated

Reil [10]

Answer:

Step-by-step explanation:

Using the sine ratio in the right triangle.

sinC = $\frac{opposite}{hypotenuse}$ = $\frac{AB}{BC}$ = $\frac{16}{28}$ , thus

∠ C = $sin^{-1}$ ( $\frac{16}{28}$ ) ≈ 34.85° ( to 2 dec. places )

8 0

2 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

2 years ago

Pls help plllllllssssssssssssssssssssssssssssss helpppppppppppppppppppppppp

hjlf

Sorry don’t now the answer to this problem

5 0

2 years ago

Which property of equality would you use to solve the equation 14x=56

Oliga [24]

Okay so divide 56 by 14 and so x = 4

4 0

2 years ago