Question

FInd the equation for the line that passes through the point (0,3), and that is perpendicular to the Line with the equation (y-1)=-2(x-1)

Answer 1

Answer:

2y = x+6

Step-by-step explanation:

From (y-1) = -2(x-1)

y-1 = -2x+2

y=-2x+2+1

y=-2x+3 compare with y = mx +C

m1= -2

For perpendicularity rule: m1m2 = -1

m2 = -1/-2 = 1/2

Equation of the line that passes through (0,3) is

y-y1 = m2(x-x2)

y-3 = 1/2(x-0) = 1/2(x)

y-3 = x/2

Multiply through by 2

2y-6 = x

2y = x+6

2y-x=6

2y-x-6=0